use*_*850 8 csv django xls file download
我是django和python的新手.在这个任务中需要一些指导.
案例:当用户点击表单上的提交按钮时,它应显示成功页面和可以下载结果的链接.结果在excel文件中.我可以使用xlwt模块创建输出到excel文件并单独显示成功页面,但不能同时显示两者.
我有:我在Windows XP上使用python 2.6运行django1.1.1.有类似的问题,但无法使其工作.
我的成功page.html有这一行
<a href="../static/example.xls">Download CSV File</a>
Run Code Online (Sandbox Code Playgroud)
urls.py:
url(r'^static/(?P<path>.*)$', send_file),
Run Code Online (Sandbox Code Playgroud)
views.py:
def send_file(request):
import os, tempfile, zipfile
from django.core.servers.basehttp import FileWrapper
"""
Send a file through Django without loading the whole file into
memory at once. The FileWrapper will turn the file object into an
iterator for chunks of 8KB.
"""
filename = "C:/example.xls" # Select your file here.
wrapper = FileWrapper(file(filename),"rb")
response = HttpResponse(wrapper, content_type='text/plain')
#response['Content-Length'] = os.path.getsize(filename)
return response
Run Code Online (Sandbox Code Playgroud)
当我点击链接时,它会给出路径错误
send_file() got an unexpected keyword argument 'path'
Request Method: GET
Request URL: localhost:8000/webinput/static/example.xls
Exception Type: TypeError
Exception Value:
send_file() got an unexpected keyword argument 'path'
Run Code Online (Sandbox Code Playgroud)
BTW example.xls位于C:/example.xls和静态文件夹中
结构体:
我也有这两个模块.如果我使用backup_to_csv它工作正常但它没有链接直接下载.当我已有文件时如何做同样的事情.如果还有其他方法我不需要存储文件,那也没关系.
def xls_to_response(xls,fname):
response = HttpResponse(mimetype="application/ms-excel")
response['Content-Disposition'] = 'attachment; filename=%s' % fname
xls.save(response)
return response
Run Code Online (Sandbox Code Playgroud)
def backup_to_csv(request,row):
response = HttpResponse(mimetype='text/csv')
response['Content-Disposition'] = 'attachment; filename="backup.csv"'
writer = csv.writer(response, dialect='excel')
#code for writing csv file go here...
for i in row:
writer.writerow(i)
return response
Run Code Online (Sandbox Code Playgroud)
现在它可以工作,但我不得不将文件扩展名从excel(.xls)更改为csv.
我的urls.py = url(r'^static/example.txt', send_file)
我的HTML链接= <a href="../static/example.txt">Download CSV File</a>
我的view.py
def send_file(request):
import os, tempfile, zipfile
from wsgiref.util import FileWrapper
from django.conf import settings
import mimetypes
filename = "C:\ex2.csv" # Select your file here.
download_name ="example.csv"
wrapper = FileWrapper(open(filename))
content_type = mimetypes.guess_type(filename)[0]
response = HttpResponse(wrapper,content_type=content_type)
response['Content-Length'] = os.path.getsize(filename)
response['Content-Disposition'] = "attachment; filename=%s"%download_name
return response
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
16853 次 |
| 最近记录: |