使用itemgetter对dict列表进行排序

Question

这是我的字典:

a = [{"id":1,"data":{"age":16,"name":a}}, 
     {"id":3,"data":{"age":35,"name":b}}, 
     {"id":2,"data":{"age":9,"name":c}}]

我想按字段"年龄"对其进行排序.

随lambda我使用:

sorted(a, key=lambda k: k['data']['age'])

怎么做itemgetter？

Answer 1

你最好先给 "a"、"b" 和 "c" 添加引号，否则你会混淆 dict a 和 char "a"

a = [{"id":1,"data":{"age":16,"name":"a"}}, 
     {"id":3,"data":{"age":35,"name":"b"}}, 
     {"id":2,"data":{"age":9,"name":"c"}}]

为了itemgetter：

from operator import itemgetter

a = [{"id":1,"data":{"age":16,"name":"a"}}, 
     {"id":3,"data":{"age":35,"name":"b"}}, 
     {"id":2,"data":{"age":9,"name":"c"}}]

l=sorted(a, key = lambda k : itemgetter('age')(itemgetter('data')(k)) )

print (l)