表
recipe_food_xref
recipe_id int
food_id int
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需要找到recipe_food_xref中的一条记录,其中食谱只有一种食物,食物是特定食物.
它完美地融入了自身:
SELECT x1.recipe_id FROM recipe_food_xref x1
INNER JOIN recipe_food_xref x2 ON x2.recipe_id = x1.recipe_id
WHERE x1.food_id = 1
GROUP BY x1.recipe_id
HAVING COUNT(x2.recipe_id) = 1
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这看起来有点难看,我想知道是否有更好的方法.
这是一个包含一些示例数据的SqlFiddle.基本上我想找到recipe_id:1,因为它有food_id:1并且没有多个food_id
SELECT recipe_id
FROM recipe_food_xref
GROUP BY recipe_id
HAVING sum(case when food_id = 1 then 1 else 0 end) = 1
and sum(case when food_id <> 1 then 1 else 0 end) = 0
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