use*_*901 19 sql grouping histogram
我在SQL Server中有以下表:
-----------------------------
ID Age Gender
1 30 F
2 35 M
3 32 M
4 18 F
5 21 F
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我需要做的是执行一个查询,该查询将给定范围内的记录分组并计算出现的次数.结果需要稍后在直方图(条形图)中显示.我尝试了类似以下的查询:
SELECT
count(CASE WHEN Age>= 10 AND Age < 20 THEN 1 END) AS '10 - 20',
count(CASE WHEN Age>= 21 AND Age < 30 THEN 1 END) AS '21 - 30',
count(CASE WHEN Age>= 31 AND Age < 35 THEN 1 END) AS '31 - 35',
count(CASE WHEN Age>= 36 AND Age < 40 THEN 1 END) AS '36 - 40',
FROM (SELECT Age FROM Attendees) AS AgeGroups
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目前,这可以解决问题,但不考虑性别列.它将产生一行,计算每个年龄组的频率:
10-20 21-30 31-35 36-40
0 22 21 13
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如果考虑性别,则应为每个性别显示两个记录.我需要看到类似的东西:
Gender 10-20 21-30 31-35 36-40
M 0 12 9 6
F 0 10 12 7
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我该如何处理这个问题?
Lam*_*mak 33
只需将Gender列添加到您的SELECT,然后执行GROUP BY.
SELECT
Gender,
count(CASE WHEN Age>= 10 AND Age < 20 THEN 1 END) AS [10 - 20],
count(CASE WHEN Age>= 21 AND Age < 30 THEN 1 END) AS [21 - 30],
count(CASE WHEN Age>= 31 AND Age < 35 THEN 1 END) AS [31 - 35],
count(CASE WHEN Age>= 36 AND Age < 40 THEN 1 END) AS [36 - 40]
FROM Attendees AS AgeGroups
GROUP BY Gender
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