Python pandas数据帧添加以前的行值

Question

我有一个像这样的pandas数据框:

                     AAPL   IBM  GOOG  XOM
2011-01-10 16:00:00  1500     0     0    0
2011-01-11 16:00:00     0     0     0    0
2011-01-12 16:00:00     0     0     0    0
2011-01-13 16:00:00 -1500  4000     0    0
2011-01-14 16:00:00     0     0     0    0
2011-01-18 16:00:00     0     0     0    0

我的目标是通过添加前面的行值来填充行.结果如下所示:

                     AAPL   IBM  GOOG  XOM
2011-01-10 16:00:00  1500     0     0    0
2011-01-11 16:00:00  1500     0     0    0
2011-01-12 16:00:00  1500     0     0    0
2011-01-13 16:00:00     0  4000     0    0
2011-01-14 16:00:00     0  4000     0    0
2011-01-18 16:00:00     0  4000     0    0

我尝试用数据帧索引进行迭代

    for date in df.index:

并用日期增加日期

    dt_nextDate = date + dt.timedelta(days=1)

但数据框索引中存在间隙,表示周末.

我可以从第二行到结尾遍历索引,返回上一行并添加值吗？

Answer 1

您的示例结果不是示例算法的输出,因此我不确定您要求的是什么？

您显示的所需结果是累积总和,您可以使用:

>>> df.cumsum()
                    AAPL   IBM  GOOG  XOM
index                                    
2011-01-1016:00:00  1500     0     0    0
2011-01-1116:00:00  1500     0     0    0
2011-01-1216:00:00  1500     0     0    0
2011-01-1316:00:00     0  4000     0    0
2011-01-1416:00:00     0  4000     0    0
2011-01-1816:00:00     0  4000     0    0

但是你想要解释的东西和你展示的算法,更有可能是窗口大小等于2的滚动总和:

>>> result = pd.rolling_sum(df, 2)
>>> result
                    AAPL   IBM  GOOG  XOM
index                                    
2011-01-1016:00:00   NaN   NaN   NaN  NaN
2011-01-1116:00:00  1500     0     0    0
2011-01-1216:00:00     0     0     0    0
2011-01-1316:00:00 -1500  4000     0    0
2011-01-1416:00:00 -1500  4000     0    0
2011-01-1816:00:00     0     0     0    0

要修复NaNs只做:

>>> result.iloc[0,:] = df.iloc[0,:]
>>> result
                    AAPL   IBM  GOOG  XOM
index                                    
2011-01-1016:00:00  1500     0     0    0
2011-01-1116:00:00  1500     0     0    0
2011-01-1216:00:00     0     0     0    0
2011-01-1316:00:00 -1500  4000     0    0
2011-01-1416:00:00 -1500  4000     0    0
2011-01-1816:00:00     0     0     0    0