String Parse,JSON Stringify和GSON Parse of Date失败

Gui*_*lmi 6 javascript java json gson

我把这个String并解析为一个Javascript对象.

{
"startTime": 233432420233,
"endTime": 233432431000,
"bufferingDelays": [
    {
        "time": 233432420233,
        "delayLength": 100
    },
    {
        "time": 233432420433,
        "delayLength": 50
    },
    {
        "time": 233432420833,
        "delayLength": 75
    }
    ]
}
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这是执行解析的Javascript代码,然后转换为JSON字符串:

var reportObject = jQuery.parseJSON(reportJSONString);

reportObject.startTime = new Date(reportObject.startTime);
reportObject.endTime = new Date(reportObject.endTime);

for (var i = 0; i < reportObject.bufferingDelays.length; i++)
{                        
    var delay = reportObject.bufferingDelays[i];
    delay.time = new Date( delay.time );

    reportObject.bufferingDelays[i] = delay;
}

var reportObjectFinalString = JSON.stringify( reportObject );
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JSON转换产生的日期之一是:1977-05-25T18:20:20.233Z.我认为尾随'Z'很糟糕.

现在在Java中我尝试将其解析为Java对象,如下所示:

Gson gson = new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ").create();
Report report = gson.fromJson( jsonBuilder.toString(), Report.class );   
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但是我得到了这个例外:

SEVERE: Servlet.service() for servlet [ReportServlet] in context with path [/Report] threw exception [com.google.gson.JsonSyntaxException: 1977-05-25T18:20:20.233Z] with root cause
java.text.ParseException: Unparseable date: "1977-05-25T18:20:20.233Z"
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Sot*_*lis 10

你需要引用Z

Gson gson = new GsonBuilder().setDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").create();
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SimpleDateFormat(在使用GsonBuilder)主罚未加引号Z的意思,你的日期字符串没有一个时区.