Gra*_*ray 18
public static int min(int a, int b) {
return (a <= b) ? a : b;
}
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public static long min(long a, long b) {
return (a <= b) ? a : b;
}
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public static float min(float a, float b) {
if (a != a) return a; // a is NaN
if ((a == 0.0f) && (b == 0.0f) && (Float.floatToIntBits(b) == negativeZeroFloatBits)) {
return b;
}
return (a <= b) ? a : b;
}
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public static double min(double a, double b) {
if (a != a) return a; // a is NaN
if ((a == 0.0d) && (b == 0.0d) && (Double.doubleToLongBits(b) == negativeZeroDoubleBits)) {
return b;
}
return (a <= b) ? a : b;
}
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更多信息:这里
til*_*ner 10
返回两个int值中较小的一个.也就是说,结果参数更接近Integer.MIN_VALUE的值.如果参数具有相同的值,则结果是相同的值.
行为:
Math.min(1, 2) => 1
Math.min(1F, 2) => 1F
Math.min(3D, 2F) => 2D
Math.min(-0F, 0F) => -0F
Math.min(0D, -0D) => -0D
Math.min(Float.NaN, -2) => Float.NaN
Math.min(-2F, Double.NaN) => Double.NaN
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java.lang.Math和java.lang.StrictMath来源:
public static int min(int a, int b) {
return (a <= b) ? a : b;
}
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java.lang.Math Bytecode(javap -c Math.classOracle的JDK的JRE的rt.jar):
public static int min(int, int);
Code:
0: iload_0 // loads a onto the stack
1: iload_1 // loads b onto the stack
2: if_icmpgt 9 // pops two ints (a, b) from the stack
// and compares them
// if b>a, the jvm continues at label 9
// else, at the next instruction, 5
// icmpgt is for integer-compare-greater-than
5: iload_0 // loads a onto the stack
6: goto 10 // jumps to label 10
9: iload_1 // loads
10: ireturn // returns the currently loaded integer
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如果在比较5是真实的,一个将被装载时,JVM将跳到10,并返回一个,如果该比较产生假的,它将跳到9,这将载入并返回b.
内在性:
Java 8 Hotspot JVM的这个.hpp文件暗示它使用优化的机器代码进一步优化Math.min:
do_intrinsic(_min, java_lang_Math, min_name, int2_int_signature, F_S)
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这意味着Java 8 Hotspot JVM将不会执行上述字节码.但是,这与JVM到JVM不同,这也是我解释字节码的原因!
希望你现在知道所有关于Math.min的知识!:)