您在范围内没有隐式应用程序:使用Oracle的PlayFramework

Question

尝试使用play框架访问oracle DataSource时出现以下错误:

sbt.PlayExceptions$CompilationException: Compilation error[You do not have an implicit Application in scope. If you want to bring
the current running Application into context, just add import play.api.Play.current]

build.properties:

sbt.version=0.12.2
db.default.driver=oracle.jdbc.driver.OracleDriver
db.default.url="jdbc:oracle:thin:@(.....basic))))"
db.default.user="username"
db.default.pass="passowrd"

Controller Application.scala如下:

package controllers

import play.api._
import play.api.mvc._
import play.api.db._


object Application extends Controller {

  val d = DB.getDataSource();

  def index = Action { request => Ok("something") } 

}

是什么导致了这个问题.一切看起来都对我不对.

仅供参考.玩!2.1.4(使用Java 1.6.0_24和Scala 2.10.0)

-谢谢

Answer 1

错误消息实际上是告诉您该怎么做:您没有在作用域中隐式应用程序.如果要将当前运行的Application引入上下文,只需添加import play.api.Play.current.

import play.api.Play.current

这就是getDataSource方法的样子:

  def getDataSource(name: String = "default")(implicit app: Application): DataSource = app.plugin[DBPlugin].map(_.api.getDataSource(name)).getOrElse(error)

正如您所看到的,它在第二个参数列表中采用了隐式Application,并且编译器正在寻找可以在导入中找到的隐式声明的Application.