23k*_*23k 0 java arrays blackjack
我正在尝试制作一个非常简单的黑杰克游戏,我在从阵列列表中绘制卡片并将它们放入玩家手中时遇到问题,并且经销商手...
这是我到目前为止所有愿意提供帮助的人将不胜感激.
我也意识到我很多人都没有以最有效的方式做到这一点......
卡片列表
import java.util.ArrayList;
public class deck {
ArrayList<card> deck = new ArrayList<card>();
public deck () {
deck = new ArrayList<card>();
//Spades
deck.add(new card ("2", "Spades"));
deck.add(new card ("3", "Spades"));
deck.add(new card ("4", "Spades"));
deck.add(new card ("5", "Spades"));
deck.add(new card ("6", "Spades"));
deck.add(new card ("7", "Spades"));
deck.add(new card ("8", "Spades"));
deck.add(new card ("9", "Spades"));
deck.add(new card ("10", "Spades"));
deck.add(new card ("2", "Spades"));
deck.add(new card ("J", "Spades"));
deck.add(new card ("Q", "Spades"));
deck.add(new card ("K", "Spades"));
deck.add(new card ("A", "Spades"));
//Clubs
deck.add(new card ("2", "Clubs"));
deck.add(new card ("3", "Clubs"));
deck.add(new card ("4", "Clubs"));
deck.add(new card ("5", "Clubs"));
deck.add(new card ("6", "Clubs"));
deck.add(new card ("7", "Clubs"));
deck.add(new card ("8", "Clubs"));
deck.add(new card ("9", "Clubs"));
deck.add(new card ("10", "Clubs"));
deck.add(new card ("2", "Clubs"));
deck.add(new card ("J", "Clubs"));
deck.add(new card ("Q", "Clubs"));
deck.add(new card ("K", "Clubs"));
deck.add(new card ("A", "Clubs"));
//Hearts
deck.add(new card ("2", "Hearts"));
deck.add(new card ("3", "Hearts"));
deck.add(new card ("4", "Hearts"));
deck.add(new card ("5", "Hearts"));
deck.add(new card ("6", "Hearts"));
deck.add(new card ("7", "Hearts"));
deck.add(new card ("8", "Hearts"));
deck.add(new card ("9", "Hearts"));
deck.add(new card ("10", "Hearts"));
deck.add(new card ("2", "Hearts"));
deck.add(new card ("J", "Hearts"));
deck.add(new card ("Q", "Hearts"));
deck.add(new card ("K", "Hearts"));
deck.add(new card ("A", "Hearts"));
//Diamonds
deck.add(new card ("2", "Diamonds"));
deck.add(new card ("3", "Diamonds"));
deck.add(new card ("4", "Diamonds"));
deck.add(new card ("5", "Diamonds"));
deck.add(new card ("6", "Diamonds"));
deck.add(new card ("7", "Diamonds"));
deck.add(new card ("8", "Diamonds"));
deck.add(new card ("9", "Diamonds"));
deck.add(new card ("10", "Diamonds"));
deck.add(new card ("2", "Diamonds"));
deck.add(new card ("J", "Diamonds"));
deck.add(new card ("Q", "Diamonds"));
deck.add(new card ("K", "Diamonds"));
deck.add(new card ("A", "Diamonds"));
}
public ArrayList<card> getCards(){
return deck;
}
public card deal(){
card one = deck.get((int) (Math.random() * deck.size()));
deck.remove(one);
return one;
}
}
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球员和经销商手类
这里是我要用数组中的两个随机卡填充dealPlayer()和dealDealer()的地方,我现在只是在一个树桩上,似乎无法找出任何可行的... ...提前感谢帮助,如果我需要发布任何其他内容,请告诉我!
import java.util.ArrayList;
public class dealer {
deck deck = new deck();
String dealerTopCardString = "";
card playerHandCard;
card dealerHandCard;
ArrayList<card> dealerHand = new ArrayList<card>();
ArrayList<card> playerHand = new ArrayList<card>();
public void start() {
dealerHand = new ArrayList<card>();
playerHand = new ArrayList<card>();
}
public void dealPlayer() {
//LOOKING FOR HELP HERE
}
public void dealDealer() {
//LOOKING FOR HELP HERE
}
public String getPlayerHand() {
String playerHandString = "";
for (int i = 0; i < playerHand.size(); i++)
playerHandCard = playerHand.get(i);
card card = new card(playerHandCard.getValue(), playerHandCard.getSuit());
playerHandString += "\n";
playerHandString += card.getValue();
playerHandString += "\t";
playerHandString += card.getSuit();
return playerHandString;
}
public String getDealerHand() {
String dealerHandString = "";
for (int i = 0; i < dealerHand.size(); i++)
dealerHandCard = dealerHand.get(i);
card card = new card(dealerHandCard.getValue(), dealerHandCard.getSuit());
dealerHandString += "\n";
dealerHandString += card.getValue();
dealerHandString += "\t";
dealerHandString += card.getSuit();
return dealerHandString;
}
public String getDealerTopCard(){
return getDealerTopCard;
}
public int getPlayerHandValue(){
return getPlayerHandValue;
}
public int getDealerHandValue(){
return getDealerHandValue;
}
public void resetDealerHand(){
dealerHand.clear();
}
public void resetPlayerHand(){
playerHand.clear();
}
}
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当您发布问题时,通常最佳做法是说出您尝试过的内容.这样,其他人可以帮助您了解您可能出错的地方.
我将就如何解决问题向您提供一些一般性建议.如果您在实施它时遇到特定问题,可以提出一个新问题(或根据其相关程度更新此问题).
在真正的二十一点游戏中,你可以将牌组洗牌,然后移除前4张牌.你可以在这里做同样的事情:
remove方法删除卡组中的第一个或最后一个元素.)这看起来可能是家庭作业,因此您可能需要使用ArrayList.这不是最好的数据结构.如果你有选择,我会改用ArrayDeque.它具有高效率pop()和remove()采取的第一个或最后一个项目从收集的方法.
(提示:"deque"代表双端队列,但它的发音是"deck".这是因为它在概念上就像一副牌......)