Okk*_*kky 4 javascript jquery jsonpath
您如何获得对象的所有子节点的JSONPath?
例如:
var data = [{
"key1": {
"children": [{
"key2": "value",
"key3": "value",
"key4": {}
}, {
"key2": "value",
"key3": "value",
"key4": {}
}],
"key5": "value"
}
}, {
"key1": {
"children": {
"key2": "value",
"key3": "value",
"key4": {}
},
"key5": "value"
}
}]
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我希望将数据结构中所有节点的绝对路径作为数组:
[
"data[0]['key1']['children'][0]['key2']",
"data[0]['key1']['children'][0]['key3']",
"data[0]['key1']['children'][0]['key4']",
......,
"data[0]['key1']['children'][1]['key2']",
.......,
"data[1]['key1']['children']['key2']",
..........
]
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有没有办法在JS中完成这项工作?
我编写了一个自定义代码,它将所有节点的JSON路径作为数组
function toArray(obj, name) {
var result = [];
var passName;
var tempArray = [];
for (var prop in obj) {
var value = obj[prop];
if (typeof value === 'object') {
if ($.isNumeric(prop)) {
passName = name + "[" + prop + "]";
} else {
passName = name + "['" + prop + "']";
}
tempArray = toArray(value, passName);
$.each(tempArray, function (key, value) {
result.push(value);
});
} else {
result.push(name + "['" + prop + "']");
}
}
return result;
}
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