listview with arraylist,android中的简单适配器

Question

我尝试使用arraylist和简单的适配器向listview显示一些东西.我尝试了类似下面的内容,但在我的结果中显示了arraylist的姓氏.我错了,我无法理解.

final ListView listView = (ListView) findViewById(R.id.mylist);

    ArrayList<HashMap<String, String>> list_of_bookmarks = new ArrayList<HashMap<String, String>>();

        HashMap<String, String> b = new HashMap<String, String>();

        String[] from = { "php_key","c_key","android_key","hacking_key" };
        String[] name_of_bookmarks = { "php","c","android","hacking" };

            for(int i=0;i<4;i++)
            {
              b.put(from[i],name_of_bookmarks[i]);   
              list_of_bookmarks.add(b);
            }

         };

            int[] to = { R.id.txt1,R.id.txt1,R.id.txt1,R.id.txt1};

            SimpleAdapter adapter = new SimpleAdapter(getBaseContext(), list_of_bookmarks, R.layout.list_layout, from, to);         
            listView.setAdapter(adapter);

我只是想在列表视图中显示"php","c","android","hacking".什么应该是更有效的方式来做到这一点.我是一个初学者,所以你可以建议一个更好的方式,我应该遵循

Answer 1

我给你的建议是创建一个单独的类来扩展Adapter(或者它的一些子类)

这是一个String数组适配器的简单示例.

package ro.gebs.captoom.adapters;

import android.content.Context;
import android.view.View;
import android.view.ViewGroup;
import antistatic.spinnerwheel.adapters.AbstractWheelTextAdapter;

import com.example.captoom.R;

public class LanguagesAdapter extends AbstractWheelTextAdapter {
    // Countries names
    private String languages[];

    public LanguagesAdapter(Context context) {
        super(context, R.layout.lang_item, NO_RESOURCE);
        languages = context.getResources().getStringArray(R.array.lang_array);
        setItemTextResource(R.id.language_txt);
    }

    @Override
    public View getItem(int index, View cachedView, ViewGroup parent) {
        View view = super.getItem(index, cachedView, parent);
        return view;
    }

    @Override
    public int getItemsCount() {
        return languages.length;
    }

    @Override
    protected CharSequence getItemText(int index) {
        return languages[index];
    }
}

而且使用方法很简单,只需使用该方法即可 .setAdapter();

或者使用arrayAdapter的另一个示例:

package apc.example;

import java.util.ArrayList;

import utils.BitmapManager;
import android.app.Activity;
import android.content.Context;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ImageView;
import android.widget.TextView;

public class PersonAdapter extends ArrayAdapter<Person> {

    Context context;
    int layoutResourceId;
    ArrayList<Person> data = null;

    public PersonAdapter(Context context, int layoutResourceId,
            ArrayList<Person> data) {
        super(context, layoutResourceId, data);
        this.layoutResourceId = layoutResourceId;
        this.context = context;
        this.data = data;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View row = convertView;
        ItemHolder holder = null;

        if (row == null) {
            LayoutInflater inflater = ((Activity) context).getLayoutInflater();
            row = inflater.inflate(layoutResourceId, parent, false);

            holder = new ItemHolder();
            holder.imgIcon = (ImageView) row.findViewById(R.id.icon);
            holder.txtName = (TextView) row.findViewById(R.id.title);
            holder.txtDescription = (TextView) row.findViewById(R.id.desc);

            row.setTag(holder);
        } else {
            holder = (ItemHolder) row.getTag();
        }

        Person bean = data.get(position);
        holder.txtName.setText(bean.getName());
        holder.txtDescription.setText(bean.getDescription());


        Bitmap b = BitmapFactory.decodeResource(context.getResources(), R.drawable.user);
        BitmapManager.INSTANCE.setPlaceholder(b);
        BitmapManager.INSTANCE.loadBitmap(bean.getUrl(), holder.imgIcon, 80, 80);

        return row;
    }

    public static class ItemHolder {
        public ImageView imgIcon;
        TextView txtName;
        TextView txtDescription;
    }

    public void updateAdapter(ArrayList<Person> pers){
        this.data = pers;
    }
}

这是一个适用于更复杂类的适配器的示例,该类具有更多字段而不是简单字符串.但这很容易被修改为ArrayAdapter<String>然后从那里开始.

无论如何,我认为为listviews编写自定义适配器始终是最佳做法.

希望这可以帮助!

Answer 2

main.xml中

<LinearLayout  

    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="60dp"   >


    <ListView
        android:id="@+id/zone_list"
        android:layout_marginBottom="70dp"
        android:background="@drawable/batteryborder"
        android:layout_width="match_parent"
        android:layout_height="wrap_content" >
    </ListView>

</LinearLayout>

setlanguage.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout 
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="60dp">

    <TextView
        android:id="@+id/tvName"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:textSize="18dp"
        android:gravity="center_vertical" />

</LinearLayout>

添加onCreate()活动文件的

ListView listView;

String[] from = { "php_key","c_key","android_key","hacking_key" };

ArrayAdapter arrayAdapter;

listView = (ListView) findViewById(R.id.zone_list); 

arrayAdapter = new ArrayAdapter(this,R.layout.setlanguage, R.id.tvName, from);

listView.setAdapter(arrayAdapter);