我有这两个表:
表一:用户
id name home_location job_location
1 Jack 40 5
2 Rocky 50 4
3 Tom 24 9
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表二:面积
area_id area_name
5 Bukit Batok
4 Bukit Panjang
9 Boon Lay
40 Pioneer
50 Choa Chu Kang
24 Clementi
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我想要这样的结果:
ID name home_location job_location
1 Jack Pioneer Bukit Batok
2 Rocky Choa Chu Kang Bukit Panjang
3 Tom Clementi Boon Lay
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由于我在sql查询中不好,所以如何编写select查询.任何想法或建议?谢谢.
试试吧
SELECT id as ID,
name,
area_1.area_name as home_location,
area_2.area_name as job_location,
area_1.area_id as home_location_id,
area_2.area_id as job_location_id
FROM user
INNER JOIN
area AS area_1
ON area_1.area_id = user.home_location
INNER JOIN
area AS area_2
ON area_2.area_id = user.job_location
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并尝试避免mysql_*由于整个ext/mysql PHP扩展而导致的语句,该扩展提供了以前缀命名的所有函数mysql_*,将来PHP v5.5.0会被正式弃用并将被删除.
还有两个其他MySQL扩展可以更好地使用:MySQLi并且PDO_MySQL,可以使用其中任何一个而不是ext/mysql.