Ahm*_*aya 1 oracle performance plsql
我必须有表,每个表至少有35M数据.我编写了一个批量更新脚本,如下所示我想知道我需要调整Limit=10000参数来运行此脚本以获得更好的性能.
DECLARE
CURSOR rec_cur IS
SELECT id,sirname
FROM table_user;
TYPE num_tab_t IS TABLE OF NUMBER;
TYPE vc2_tab_t IS TABLE OF VARCHAR2(15);
id_tab NUM_TAB_T;
sirname_tab VC2_TAB_T;
BEGIN
OPEN rec_cur;
LOOP
FETCH rec_cur BULK COLLECT INTO id_tab, sirname_tab LIMIT 10000;
EXIT WHEN id_tab.COUNT() = 0;
FORALL i IN id_tab.FIRST .. id_tab.LAST
UPDATE table_user_backup
SET sirname = sirname_tab(i)
, sirname_date = sysdate
WHERE id = id_tab(i);
END LOOP;
CLOSE rec_cur;
END;
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我已经测试了三种可能的批量更新方式,分享它们每个经过的时间.它表明SQL比pl-sql forall批量更新更好.更改限制参数范围1000-100000后,我看不出任何差异
-- Bulk update --for 2.5M entries
--Takes 4 Minutes
DECLARE
CURSOR rec_cur IS
SELECT id,name
FROM table_user;
BEGIN
FOR sub in rec_cur
LOOP
UPDATE table_user_backup
SET name_date = sysdate
WHERE id = sub.id;
END LOOP;
END;
--takes 2.5 minutes
DECLARE
CURSOR rec_cur IS
SELECT id,name
FROM table_user;
TYPE num_tab_t IS TABLE OF NUMBER;
TYPE vc2_tab_t IS TABLE OF VARCHAR2(20);
id_tab NUM_TAB_T;
name_tab VC2_TAB_T;
BEGIN
OPEN rec_cur;
LOOP
FETCH rec_cur BULK COLLECT INTO id_tab, name_tab LIMIT 10000;
EXIT WHEN id_tab.COUNT() = 0;
FORALL i IN id_tab.FIRST .. id_tab.LAST
UPDATE table_user_backup
SET name = name_tab(i)
, name_date = sysdate
WHERE id = id_tab(i);
END LOOP;
CLOSE rec_cur;
END;
--SQL is faster than pl sql
--takes 2.0 minutes
UPDATE table_user_backup tu_backup
SET (name, name_date) = (SELECT name, sysdate
FROM table_user tu
WHERE tu_backup.id = tu.id)
WHERE EXISTS( SELECT 1
FROM table_user tu
WHERE tu.id=tu_backup.id);
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如果这是实际的脚本,那么摆脱PL/SQL处理并在SQL中执行所有操作应该更有效.PL/SQL中的批量处理比PL/SQL中的逐行处理更有效,但SQL比PL/SQL更有效.
UPDATE table_user_backup tub
SET (sirname, sirname_date) = (SELECT sirname, sysdate
FROM table_user tu
WHERE tu.id = tub.id)
WHERE EXISTS( SELECT 1
FROM table_user
WHERE tu.id = tub.id);
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如果这不够有效,您需要告诉我们哪些索引可用,查询计划是什么,涉及多少行等.