sim*_*dam 6 android get android-volley
请问,Volley会自动将我的GET参数添加到URL吗?对我来说,它不是这样工作,也是在查看源代码时,我无法找到任何getParams方法的调用.那么我应该自己构建URL吗?这根本不是问题,我只是认为当有像getParams这样的方法时,它可以为我做到这一点:)
更新:以下是我的代码..
public class BundleRequest extends com.android.volley.Request<Bundle>{
private String token;
private OnAuthTokenValidatorResponseListener mListener;
private final Map<String, String> mParams = new HashMap<String, String>();;
public BundleRequest(int method, String url, Response.ErrorListener listener) {
super(method, url, listener);
}
public BundleRequest(int method, String url,OnAuthTokenValidatorResponseListener providedListener, Response.ErrorListener listener, String token) {
super(method, url, listener);
this.token = token;
mListener = providedListener;
mParams.put(AuthenticatorConfig.TOKEN_VALIDATION_PARAMNAME, token);
}
@Override
public Map<String, String> getParams() throws AuthFailureError {
return mParams;
}
@Override
protected Response<Bundle> parseNetworkResponse(NetworkResponse httpResponse) {
switch (httpResponse.statusCode) {
case AuthTokenValidator.TOKEN_VALID_RESPONSE_CODE:
//token is ok
JSONObject response;
try {
response = new JSONObject(new String(httpResponse.data, HttpHeaderParser.parseCharset(httpResponse.headers)));
Bundle userDataResponse = new Bundle();
userDataResponse.putInt("responseCode", httpResponse.statusCode);
userDataResponse.putString("username", response.getString("user_id"));
userDataResponse.putString("email", response.getString("user_email"));
userDataResponse.putString("expiresIn", response.getString("expires_in"));
userDataResponse.putString("scope", response.getJSONArray("scope").getString(0));
userDataResponse.putString("token", token);
return Response.success(userDataResponse, HttpHeaderParser.parseCacheHeaders(httpResponse));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
return Response.error(new VolleyError("Unsupported encoding"));
} catch (JSONException e) {
e.printStackTrace();
return Response.error(new VolleyError("Problem while parsing JSON"));
}
case AuthTokenValidator.TOKEN_INVALID_RESPONSE_CODE:
//token is not valid
mListener.onValidatorResponse(httpResponse.statusCode);
try {
mListener.onValidatorResponse(parseOnErrorResponse(new String(httpResponse.data, HttpHeaderParser.parseCharset(httpResponse.headers))));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
default:
return Response.error(new VolleyError("Error status code:" + httpResponse.statusCode));
}
}
protected int parseOnErrorResponse(String responseBody) {
try {
JSONObject response = new JSONObject(responseBody);
String moreInfo = response.getString("more_info");
if (moreInfo.equals("Token was not recognised")) {
return AuthTokenValidator.TOKEN_WAS_NOT_RECOGNISED;
} else if (moreInfo.equals("Token has expired")) {
return AuthTokenValidator.TOKEN_HAS_EXPIRED;
} else if (moreInfo.equals("Client doesn't exist anymore")) {
return AuthTokenValidator.CLIENT_DOES_NOT_EXIST_ANYMORE;
} else if (moreInfo.equals("Client is locked")) {
return AuthTokenValidator.CLIENT_IS_LOCKED;
} else {
return AuthTokenValidator.UNKNOWN_ERROR;
}
} catch (JSONException e) {
e.printStackTrace();
return AuthTokenValidator.UNKNOWN_ERROR;
}
}
@Override
protected void deliverResponse(Bundle response) {
mListener.onGetUserDataResponse(response);
}
}
Run Code Online (Sandbox Code Playgroud)
实际上,params参数现在是多余的
Ita*_*ski 10
getParams() 没有在GET方法上调用,因此在发送请求之前,您似乎必须将其添加到URL.
看看JavaDoc:
返回用于POST或PUT请求的参数Map.
可以抛出{@link AuthFailureError},因为可能需要进行身份验证才能提供这些值.
请注意,您可以直接覆盖{@link #getBody()}以获取自定义数据.
在auth失败的情况下@throws AuthFailureError
| 归档时间: |
|
| 查看次数: |
9489 次 |
| 最近记录: |