VB.net Mid作为左操作员特殊(奇怪?)行为

Ale*_*ini 5 .net vb.net

今天,在与我的同事交谈时,脑子里出现了一些奇怪的东西.

处理来自vb6的字符串的"秘密"方式,如:

 Dim strSomeString as String
 strSomeString = "i am phat" 
 Mid$(strSomeString, 6,4) = "hack"
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这将放在i am hack里面strSomeString.

虽然对vb6中支持的这种奇怪感到惊讶,但当我读到它在VB.Net中也得到支持时(我可能与旧代码的兼容性),我完全被吹了.

Dim TestString As String
' Initializes string.
TestString = "The dog jumps"
' Returns "The fox jumps".
Mid(TestString, 5, 3) = "fox"
' Returns "The cow jumps".
Mid(TestString, 5) = "cow"
' Returns "The cow jumpe".
Mid(TestString, 5) = "cow jumped over"
' Returns "The duc jumpe".
Mid(TestString, 5, 3) = "duck"
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我的问题是:它在技术上如何运作?什么是Mid像个在特定的情况呢?(方法?函数?扩展方法?)

Bin*_*ier 8

它被转换为Microsoft.VisualBasic.CompilerServices.StringType中对此函数的MSIL调用

Public Shared Sub MidStmtStr ( _
    ByRef sDest As String, _
    StartPosition As Integer, _
    MaxInsertLength As Integer, _
    sInsert As String _
)
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这个编译器技巧纯粹是为了向后兼容.它内置于编译器中,因此不是您可以在自己的类型上实现的技巧.

所以

Mid(TestString, 5, 3) = "fox"
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MidStmtStr(TestString, 5, 3, "fox")
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希望这可以帮助,