javascript用语言打破句子

Question

什么是一个很好的策略,可以将完整的单词带入具有后续特征的数组中.

例.这是一个惊人的句子.

Array(
[0] => This 
[1] => is
[2] => an
[3] => amazing
[4] => sentence.
)

元素0 - 3将具有后续空格,因为句点接替第4个元素.

我在单词中的想法是说..嘿,我需要你通过间距字符来分割这些,然后一旦注入的数组元素的元素宽度达到X,就打破一个新的行.

请,gawd不要提供大量的代码.我更喜欢自己写,只要告诉我你会怎么做.

Answer 1

只需使用split:

var str = "This is an amazing sentence.";
var words = str.split(" ");
console.log(words);
//["This", "is", "an", "amazing", "sentence."]

如果你需要一个空间,你为什么不这样做呢？(之后使用循环)

var str = "This is an amazing sentence.";
var words = str.split(" ");
for (var i = 0; i < words.length - 1; i++) {
    words[i] += " ";
}
console.log(words);
//["This ", "is ", "an ", "amazing ", "sentence."]

哦,睡个好觉!

Answer 2

与Ravi的答案类似,使用match,但使用\b正则表达式中的单词边界来分割单词边界:

'This is  a test.  This is only a test.'.match(/\b(\w+)\b/g)

产量

["This", "is", "a", "test", "This", "is", "only", "a", "test"]

要么

'This is  a test.  This is only a test.'.match(/\b(\w+\W+)/g)

产量

["This ", "is  ", "a ", "test.  ", "This ", "is ", "only ", "a ", "test."]

Answer 3

试试这个

var words = str.replace(/([ .,;]+)/g,'$1§sep§').split('§sep§');

这将

1. §sep§在每个选定的分隔符后插入标记[ .,;]+
2. 将字符串拆分到标记的位置,从而保留实际的分隔符.

Answer 4

使用split和filter删除前导和尾随空格。

let str = '     This is an amazing sentence.  ',
  words = str.split(' ').filter(w => w !== '');

console.log(words);

Answer 5

如果你需要空格和最简单的点.

"This is an amazing sentence.".match(/.*?[\.\s]+?/g);

结果将是

['This ','is ','an ','amazing ','sentence.']