Uri(Uri,String)构造函数不能正常工作？

Question

这是我的代码的一部分:

Uri branches = new Uri(@"https://127.0.0.1:8443/svn/CXB1/Validation/branches");
Uri testBranch = new Uri(branches, "test");

我希望testBranches会是https://127.0.0.1:8443/svn/CXB1/Validation/branches/test,但确实如此https://127.0.0.1:8443/svn/CXB1/Validation/test.我无法理解为什么Uri(Uri,string)构造函数吃掉路径的最后部分.

Answer 1

在分支后添加斜杠

  Uri branches = new Uri(@"https://127.0.0.1:8443/svn/CXB1/Validation/branches/");
  Uri testBranch = new Uri(branches, "test");