Python：将子流程模块从v3.3导入到v2.7.4

Question

我想将subprocess模块从py v3.3 导入到v2.7，以便能够使用该timeout功能。

看了几篇文章后，我尝试了

from __future__ import subprocess

但它说：

SyntaxError: future feature subprocess is not defined

然后我发现未来没有任何功能subprocess。

那么我应该subprocess从哪里导入v3.3？

Answer 1

我认为向后移植是个好主意。这里有一个比较subprocess.call。timeout请注意，在 Python2 中，后面带有命名参数*popenargs是一个语法错误，因此向后移植有一个解决方法。其他函数的超时参数的处理方式类似。如果您对超时的实际实现方式感兴趣，您应该查看该wait方法。Popen

Python2.7子进程

def call(*popenargs, **kwargs):
    """Run command with arguments.  Wait for command to complete, then
    return the returncode attribute.

    The arguments are the same as for the Popen constructor.  Example:

    retcode = call(["ls", "-l"])
    """
    return Popen(*popenargs, **kwargs).wait()

Python3.3子进程

def call(*popenargs, timeout=None, **kwargs):
    """Run command with arguments.  Wait for command to complete or
    timeout, then return the returncode attribute.

    The arguments are the same as for the Popen constructor.  Example:

    retcode = call(["ls", "-l"])
    """
    with Popen(*popenargs, **kwargs) as p:
        try:
            return p.wait(timeout=timeout)
        except:
            p.kill()
            p.wait()
            raise

Python2.7 subprocess32 向后移植

def call(*popenargs, **kwargs):
    """Run command with arguments.  Wait for command to complete or
    timeout, then return the returncode attribute.

    The arguments are the same as for the Popen constructor.  Example:

    retcode = call(["ls", "-l"])
    """
    timeout = kwargs.pop('timeout', None)
    p = Popen(*popenargs, **kwargs)
    try:
        return p.wait(timeout=timeout)
    except TimeoutExpired:
        p.kill()
        p.wait()
        raise