下面是返回jquery函数视图的代码片段,但我想知道如何提取或获取视图html并返回到客户端.
$(function() {
$('#myddl').change(function() {
var url = $(this).data('url');
var value = $(this).val();
$('#result').load(url, { value: value })
});
});
<div id="result"></div>
Run Code Online (Sandbox Code Playgroud)
在Foo动作中你可以返回一个局部视图:
public ActionResult Foo(string value)
{
SomeModel model = ...
return PartialView(model);
}
Run Code Online (Sandbox Code Playgroud)
在web形式这种方式我extarct usercontrols或任何控件相关的HTML.
System.Web.UI.Page pageHolder = new System.Web.UI.Page();
BBAReman.facebox.FeedBack ctl = (BBAReman.facebox.FeedBack)pageHolder.LoadControl("~/UserControls/FeedBack.ascx");
System.Web.UI.HtmlControls.HtmlForm tempForm = new System.Web.UI.HtmlControls.HtmlForm();
tempForm.Controls.Add(ctl);
pageHolder.Controls.Add(tempForm);
StringWriter output = new StringWriter();
HttpContext.Current.Server.Execute(pageHolder, output, false);
outputToReturn = output.ToString();
Run Code Online (Sandbox Code Playgroud)
所以如何在mvc中做同样的事情.我想知道如何从动作方法中获取视图html.谢谢
Luc*_*uca 10
您可以使用此方法,从控制器传递ActionResult并从视图中返回html
private string RenderActionResultToString(ActionResult result)
{
// Create memory writer.
var sb = new StringBuilder();
var memWriter = new StringWriter(sb);
// Create fake http context to render the view.
var fakeResponse = new HttpResponse(memWriter);
var fakeContext = new HttpContext(System.Web.HttpContext.Current.Request,
fakeResponse);
var fakeControllerContext = new ControllerContext(
new HttpContextWrapper(fakeContext),
this.ControllerContext.RouteData,
this.ControllerContext.Controller);
var oldContext = System.Web.HttpContext.Current;
System.Web.HttpContext.Current = fakeContext;
// Render the view.
result.ExecuteResult(fakeControllerContext);
// Restore old context.
System.Web.HttpContext.Current = oldContext;
// Flush memory and return output.
memWriter.Flush();
return sb.ToString();
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
7239 次 |
| 最近记录: |