Triyng在Python 2.7中做到这一点:
>>> s = u"some\u2028text"
>>> s
u'some\u2028text'
>>> l = s.splitlines(True)
>>> l
[u'some\u2028', u'text']
Run Code Online (Sandbox Code Playgroud)
\u2028是从左到右嵌入字符,而不是\r或\n,因此不应拆分该行.有错误还是只是我的误会?
\u2028是LINE SEPARATOR,从左到右嵌入是\u202A:
>>> import unicodedata
>>> unicodedata.name(u'\u2028')
'LINE SEPARATOR'
>>> unicodedata.name(u'\u202A')
'LEFT-TO-RIGHT EMBEDDING'
Run Code Online (Sandbox Code Playgroud)
考虑换行的代码点列表很容易(虽然不容易找到)在python源代码中看到(python 2.7,我的评论):
/* Returns 1 for Unicode characters having the line break
* property 'BK', 'CR', 'LF' or 'NL' or having bidirectional
* type 'B', 0 otherwise.
*/
int _PyUnicode_IsLinebreak(register const Py_UNICODE ch)
{
switch (ch) {
// Basic Latin
case 0x000A: // LINE FEED
case 0x000B: // VERTICAL TABULATION
case 0x000C: // FORM FEED
case 0x000D: // CARRIAGE RETURN
case 0x001C: // FILE SEPARATOR
case 0x001D: // GROUP SEPARATOR
case 0x001E: // RECORD SEPARATOR
// Latin-1 Supplement
case 0x0085: // NEXT LINE
// General punctuation
case 0x2028: // LINE SEPARATOR
case 0x2029: // PARAGRAPH SEPARATOR
return 1;
}
return 0;
}
Run Code Online (Sandbox Code Playgroud)