如何在八个字符块中拆分字符串？

Question

我有以下二进制字符串

string binaryString = "110011100110011011001110011001101100111001100110110011100110011011001110001001100110011011001110";

现在我想将上面的字符串拆分为8个字符的组.例如.

11001110 11001110 11001110 11001110 11001110 11001110 

我尝试了下面的代码但没有得到预期的结果

var binary = binaryString.Where((x, y) => y % 8 == 0).ToList();

Answer 1

试试这个:

IEnumerable<string> groups =  Enumerable.Range(0, binaryString.Length / 8)
                                        .Select(i => binaryString.Substring(i * 8, 8));