在保持订单的同时重塑python列表

Question

如果我有一个python列表,其形状如下:

T = [
['07,07,2012 22:10', ['people','drama','melody','bun']],
['08,07,2012 21:04', ['queen','group']],
['08,07,2012 21:23', ['printing','market','shopping']],
['08,07,2012 21:04', ['people','bun']],
['08,11,2012 11:14', ['kangaroo']]
]

我需要的是将此列表转换为以下格式:

T =[
['07,07,2012 22:10', 'people'],
['07,07,2012 22:10', 'drama'],
['07,07,2012 22:10', 'melody'],
['07,07,2012 22:10', 'bun'],
['08,07,2012 21:04', 'queen'],
['08,07,2012 21:04', 'group'],
['08,07,2012 21:23', 'printing'],
['08,07,2012 21:23', 'market'],
['08,07,2012 21:23', 'shopping'],
['08,07,2012 21:04', 'people'],
['08,07,2012 21:04', 'bun'],
[''08,11,2012 11:14'', 'kangaroo']
]

即,对于其第一个子元素的长度大于1的每个元素(在原始列表T中),拆分第一个子元素(a[1] for a in T if len(a[1] > 1))并将其作为具有相同时间戳的另一个列表附加.也许我的话缺乏解释,但上面的例子肯定是在解释我需要做什么.任何帮助,将不胜感激.

Answer 1

使用列表理解:

[(timestamp, item) for timestamp, items in T for item in items]

这将为您提供元组列表,这可能适用于此处.但您可以修改它以获取列表列表:

[[timestamp, item] for timestamp, items in T for item in items]