backbutton确认退出app android + phonegap + jquery

Question

如何在Phonegap在线系统中使用jQuery Mobile处理Android中的物理后退按钮？我想显示确认退出应用程序(是 - 否).我尝试了很多方法但没有任何工作.

Answer 1

试试这个:

document.addEventListener("deviceready", onDeviceReady, false);

function onDeviceReady() {
    document.addEventListener("backbutton", onBackKeyDown, false); //Listen to the User clicking on the back button
}

function onBackKeyDown(e) {
    e.preventDefault();
    navigator.notification.confirm("Are you sure you want to exit ?", onConfirm, "Confirmation", "Yes,No"); 
    // Prompt the user with the choice
}

function onConfirm(button) {
    if(button==2){//If User selected No, then we just do nothing
        return;
    }else{
        navigator.app.exitApp();// Otherwise we quit the app.
    }
}

Answer 2

当第一次单击设置exitApp = true时,第二次单击后退按钮将退出应用程序.但是设置一个Interval将exitApp的状态更改为false.因此,当在1秒内点击两次按钮时,将退出应用程序.

document.addEventListener('deviceready', function() {
    var exitApp = false, intval = setInterval(function (){exitApp = false;}, 1000);
    document.addEventListener("backbutton", function (e){
        e.preventDefault();
        if (exitApp) {
            clearInterval(intval) 
            (navigator.app && navigator.app.exitApp()) || (device && device.exitApp())
        }
        else {
            exitApp = true
            history.back(1);
        } 
    }, false);
}, false);