Python url_for语法错误

Question

我有一个函数来创建如下所示的新课程,如果课程是新的,则需要0个参数,如果刚刚尝试创建但是验证失败则需要5个参数.

路线:

@app.route('/courses/new')
def new_course(*args):
    if len(args) == 5:
        ...
    else:
        ...

呼叫者,召集者:

...
return redirect(url_for('new_course',  int(request.form['id']), course_code, semester, year, student_ids))

我收到错误消息url_for()接受1个参数(给定6个).或者,如果我尝试:

...
return redirect(url_for('new_course',  args[int(request.form['id']), course_code, semester, year, student_ids]))

我收到错误消息new_course()需要5个参数(给定0)

我究竟做错了什么？

Answer 1

url_for将键值对作为参数,有关详细信息,请参阅:http://flask.pocoo.org/docs/api/#flask.url_for

这将有效:

@app.route('/courses/new/') # Added trailing slashes. For more check http://flask.pocoo.org/docs/api/#url-route-registrations
def new_course():
    # use request.args to fetch query strings
    # For example: id = request.args.get('id')

呼叫者,召集者:

return redirect(url_for('new_course',  id=int(request.form['id']), code=course_code, sem=semester, year=year, student_id=student_ids))