美好的一天!
我目前通过以下代码使用Newtonsoft Json Serializer:
private string serializeAndIgnoreEmail(UserMembership obj)
{
var json = JsonConvert.SerializeObject(obj, Formatting.Indented,
new JsonSerializerSettings() { ContractResolver = new DocumentIdContractResolver() });
return json;
}
private class DocumentIdContractResolver : CamelCasePropertyNamesContractResolver
{
protected override List<MemberInfo> GetSerializableMembers(Type objectType)
{
return base.GetSerializableMembers(objectType).Where(o => o.Name != "Email").ToList();
}
}
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每次我需要序列化一个对象时,我都会调用'serializeAndIgnoreEmail'方法.我现在想用它的加密版本替换每个属性的内容,我不知道在哪里这样做.
我的猜测是覆盖'DocumentIdContractResolver'中的一个方法,但是有很多CreateBlahBlahBlah,我觉得很难使用它们.
这是正确的方法,继续修改ContractResolver还是我应该尝试别的?
谢谢!
调用SerializeObject做两件事:根据您指定的对象创建一个JSON令牌树,并将其序列化为包含JSON的字符串.
最好的办法是分别执行以下两个步骤:首先让JSON.NET为您提供JSON令牌树,然后修改值,然后将它们序列化为JSON.
从我的头顶:
namespace JsonEncryptionTest
{
class Program
{
static void Main(string[] args)
{
var obj = new
{
To = "Some name",
Subject = "A Subject",
Content = "A content"
};
var jsonObject = JObject.FromObject(obj);
// modify the values. Just doing something here to amuse you.
var property = jsonObject.Property("Content");
var value = (string) property.Value;
property.Value = value.ToLower();
var json = jsonObject.ToString();
Console.WriteLine(json);
}
}
}
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