等于操作无法解决“ Latin1_General_CI_AI”和“ SQL_Latin1_General_CP1_CI_AS”之间的排序规则冲突

Question

我正在尝试在SQL Server 2008R2中创建一个过程，但显示此错误

等于操作无法解决“ Latin1_General_CI_AI”和“ SQL_Latin1_General_CP1_CI_AS”之间的排序规则冲突。

我创建的过程是

CREATE Procedure Ps_Quiz_OnlineTest_QuestionsWithOptions_Get --'Ques1'
  @Ques Varchar(8000)
As        
Begin

  Select 
    A.QuestionId, 
    A.QsnDesc, 
    A.CorrectOption, 
    B.OptionValue, 
    A.Marks,
    (
      Select QsnName 
      From Quiz_tblQsnsLimitMaster
      Where QsnId = @Ques) QuesPaper,
    (
      Select Durationoftest 
      From Quiz_tblQsnsLimitMaster
      Where QsnId = @Ques) QuesPaper
    From 
      Quiz_tblQsnCreationMaster A, 
      Quiz_tblQsnCreationDetail B        
    Where 
      A.QuestionId = B.QuestionId
      And A.QuestionId In (
        Select QuestionIds 
        From FN_Question_Answers_Quiz(@Ques))
      And B.QuestionId In (
        Select QuestionIds 
        From FN_Question_Answers_Quiz(@Ques))  
    Order By 
      A.QuestionId, 
      B.OptionOrder 

End    

我试图用不同的排序规则来整理表，但是没有用。我该如何解决。

Answer 1

也许这可能会有所帮助，像这样更改您的条件

Where A.QuestionId COLLATE DATABASE_DEFAULT = B.QuestionId  COLLATE DATABASE_DEFAULT

Answer 2

既然您提到每个表中的 QuestionID 都是 varchar，那么这可能是这些表之间的比较。因此，根据猜测，尝试更改该行：

Where A.QuestionId = B.QuestionId  And

至以下内容：

Where A.QuestionId = B.QuestionId COLLATE SQL_Latin1_General_CP1_CI_AS And

如果您对表使用正确的联接语法，我会更喜欢它 - 但这是另一天的事了;-)