gbn*_*gbn 14
SELECT
DATEADD(day,DATEDIFF(day,'19000107',DATEADD(month,DATEDIFF(MONTH,0,GETDATE() /*YourValuehere*/),30))/7*7,'19000107')
Run Code Online (Sandbox Code Playgroud)
编辑:我同事的正确,最终,有效的答案.
小智 5
select dateadd(day,1-datepart(dw, getdate()), getdate())
Run Code Online (Sandbox Code Playgroud)