Java Thread参数

Question

在我学习线程的过程中,这是按预期工作的

public class Game implements Runnable{

    //FIELDS
    private Thread t1;
    boolean running;

    //METHODS   

    public void start(){
        running = true;
        t1 = new Thread(this);
        t1.start();
    }


    public void run(){
        while (running){
            System.out.println("runnin");
            try {
                Thread.sleep(17);
            }
            catch (InterruptedException e) {
                        e.printStackTrace();
            }
        }
    }



}

然后,当我将线程参数更改为

t1=new Thread (new Game());

程序不再进入run方法.它们不应该是一样的吗？替换"this"关键字的另一种方法应该是什么？

编辑:我从另一个类调用start方法.

甚至在创建实例后将运行变量设置为true,它仍然为false:

public void start(){
    t1 = new Thread(new Game());
    running = true;
    t1.start();
}

Answer 1

它进入run()方法,但它立即从它返回,因为run方法循环而running为true.

在调用时new Game(),您正在构建一个新的不同的Game实例,其running字段为false.所以循环根本不循环:

public void start(){
    running = true; // set this.running to true
    t1 = new Thread(new Game()); // construct a new Game. This new Game has another, different running field, whose value is false 
    t1.start(); // start the thread, which doesn't do anything since running is false
}

将其更改为

public void start(){
    Game newGame = new Game();
    newGame.running = true;
    t1 = new Thread(newGame);
    t1.start();
}

它会做你期望的.