gra*_*aci 1 java arrays sorting arraylist comparator
假设我有两个ArrayLists:
name: [Four, Three, One, Two]
num: [4, 3, 1, 2]
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如果我这样做:Arrays.sort(num),那么我有:
name: [Four, Three, One, Two]
num: [1, 2, 3, 4]
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有没有什么方法可以对num进行排序并将其反映在名称中,这样我最终可能会:
name: [One, Two, Three, Four]
num: [1, 2, 3, 4]
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?请帮帮我.我想到了比较器和对象,但根本不知道它们.
您应该以某种方式将字段和字段关联 到一个类中,然后具有该特定类的实例列表.在此类中,提供检查数值的方法.如果对实例进行排序,那么名称字段也将按您所希望的顺序排列.namenumcompareTo()
class Entity implements Comparable<Entity> {
String name;
int num;
Entity(String name, int num) {
this.name = name;
this.num = num;
}
@Override
public int compareTo(Entity o) {
if (this.num > o.num)
return 1;
else if (this.num < o.num)
return -1;
return 0;
}
}
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测试代码可能是这样的:
public static void main(String[] args) {
List<Entity> entities = new ArrayList<Entity>();
entities.add(new Entity("One", 1));
entities.add(new Entity("Two", 2));
entities.add(new Entity("Three", 3));
entities.add(new Entity("Four", 4));
Collections.sort(entities);
for (Entity entity : entities)
System.out.print(entity.num + " => " + entity.name + " ");
}
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输出:
1 => 1 2 => 2 3 => 3 4 => 4
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