知道什么时候动画完成时动画从iOS抽象出来

Question

遇到一些问题,搜索了一些类似的问题,但无法解决问题.我有一个简单的按钮动画,我在我制作的实用程序类中使用我的项目.问题是按钮代码在动画完成之前执行.

实用程序class.m中的动画代码:

+(void)buttonBobble:(UIButton *)button{
  button.transform = CGAffineTransformMakeScale(0.8, 0.8);
  [UIView beginAnimations:@"button" context:nil];
  [UIView setAnimationDuration:.5];
  button.transform = CGAffineTransformMakeScale(1, 1);
  [UIView commitAnimations];
}

我试图确保动画在任何按钮触发代码之前完成:

[UIView animateWithDuration:0.0f delay:0.0f options: UIViewAnimationOptionTransitionNone  animations:^{
    [Utilities buttonBobble:sender];
}completion:^(BOOL finished){
    //Do stuff
}];

即使这样有效,我希望将它抽象出来,我可以做到这样的事情:

if([Utilities buttonBobble:sender]){
  //Make it send a BOOL so when it's done I execute stuff like normal
}

欢迎任何想法.

Answer 1

更改您的实用程序方法以获取一个完成块,该块封装了按钮在完成浮动时所需的操作:

+(void)buttonBobble:(UIButton *)button 
     actionWhenDone:(void (^)(BOOL))action
{
    button.transform = CGAffineTransformMakeScale(0.8, 0.8);
    [UIView animateWithDuration:0.5f animations:^{
        button.transform = CGAffineTransformMakeScale(1, 1);
     }
                     completion:action];
}

在原始按钮操作方法中,您传递该操作块而不是直接在方法中运行代码:

- (IBAction)buttonAction:(id)sender
{
    [Utilities buttonBobble:sender
             actionWhenDone:^(BOOL finished){
                // Your code here
        }];
    // Nothing here.
}

作为设计说明,您还可以考虑将该实用程序方法放在以下类别中UIButton:

@implementation UIButton (JMMBobble)

- (void)JMMBobbleWithActionWhenDone:(void (^)(BOOL))action
{
    self.transform = CGAffineTransformMakeScale(0.8, 0.8);
    [UIView animateWithDuration:0.5f animations:^{
        self.transform = CGAffineTransformMakeScale(1, 1);
     }
                     completion:action];
} 

然后动作看起来像

- (IBAction)buttonAction:(id)sender
{
    [sender JMMBobbleWithActionWhenDone:^(BOOL finished){
                // Your code here
        }];
}