PHP的MySQL密码()函数

Question

我试过研究这个,但仍然没有答案.我朋友设计的程序使用MySQL password()函数写入MySQL数据库密码.

我正在寻找一种方法来通过我设计的网络前端使用它,但仍然没有运气.有没有人有什么建议？

密码看起来就像这个例子

mysql> SET old_passwords = 0;
mysql> SELECT PASSWORD('mypass');
+-------------------------------------------+
| PASSWORD('mypass')                        |
+-------------------------------------------+
| *6C8989366EAF75BB670AD8EA7A7FC1176A95CEF4 |
+-------------------------------------------+

我只需要弄清楚如何将其转换为函数即函数password_hash

这是其余的登录查询示例

if (isset($_POST["username"], $_POST["password"], $_POST[$CONF["LOGIN_SIGNAL_TRIGGER"]])) {

    /*
        If we got a login signal, a password and a username, we will
        proceed to check login information. We will first extract
        the user row from the db.
    */
    $user = myF(myQ("
        SELECT `username`,`password`,`id`,`disable_until`,`active`
        FROM `[x]users` 
        WHERE LCASE(`username`)='".strtolower($_POST["username"])."'
    "));

    if (!$user["id"]) $GLOBALS["LOGIN_FAIL_TYPE"] = "e.user";
    elseif ($user["active"] != 1 && $CONF["LOGIN_REQUIRE_ACTIVE"]) $GLOBALS["LOGIN_FAIL_TYPE"] = "e.active";

    else {
        /*
            If the user's account 'disabled' value is greater than 
            the actual date value, and that the bruteforce protection
            system is enabled, we will show an error message
        */
        if (($user["disable_until"] > date("U")) && ($CONF["LOGIN_BRUTEFORCE_PROTECT:ENABLE"])) {
             $GLOBALS["LOGIN_FAIL_TYPE"] = "e.bruteforce";
            (isset($_SESSION["loginFailCount"])?session_unregister('loginFailCount'):false);
        }

        /*
            Account is not disabled
        */
        else {
            if ((isset($_SESSION["loginFailCount"])) && ($_SESSION["loginFailCount"] > $CONF["LOGIN_BRUTEFORCE_FAILCOUNT"])) {

                myQ("UPDATE `[x]users`
                    SET `disable_until` = ".(date("U")+$CONF["LOGIN_BRUTEFORCE_DISABLE_DURATION"])."
                    WHERE LCASE(`username`)='".strtolower($_POST["username"])."'
                    LIMIT 1"
                );

                (isset($_SESSION["loginFailCount"])?session_unregister('loginFailCount'):false);
                $GLOBALS["LOGIN_FAIL_TYPE"] = "e.bruteforce";
            }

            else {

                /*
                    All the information correct, we will proceed to login
                */
                if ($user["password"] == md5(trim($_POST["password"]))) {
                    $_SESSION["id"] = (integer)$user["id"];

                    session_write_close();

                    /*
                        Update the last login key
                    */
                    $me_last_login = me("last_login");
                    myQ("UPDATE `[x]users` SET `last_login`='".date("U")."' WHERE `id`='".me('id')."'");

                    /*
                        Route the user
                    */
                    if (!$GLOBALS["WAP_MODE"]) {
                        header("Location: ".(!$me_last_login?$CONF["LOGIN_FIRST_ROUTE_TO"]:$CONF["LOGIN_ROUTE_TO"]));
                    } else header("Location: {$CONF["WAP_LOGIN_ROUTE_TO"]}");

                } 

                else {
                    (isset($_SESSION["loginFailCount"])?$_SESSION["loginFailCount"]++:$_SESSION["loginFailCount"]=1);
                    $GLOBALS["LOGIN_FAIL_TYPE"] = "e.password";
                }
            }
        }
    }
}

if ((isset($_GET[$CONF["LOGOUT_SIGNAL_TRIGGER"]])) && (!isset($_POST[$CONF["LOGIN_SIGNAL_TRIGGER"]]))) {

    /*
        Handle admin swapping
    */
    if (isset($_SESSION["swap_id"])) {
        $_SESSION["id"] = $_SESSION["swap_id"];
        session_unregister("swap_id");
        header("Location: ?L=admin.index");
    }

    else {
        (isset($_SESSION["id"])?session_unregister('id'):false);
        (isset($_SESSION["SELF_USER_DATA"])?session_unregister('SELF_USER_DATA'):false);

        header("Location: {$CONF["LOGOUT_ROUTE_TO"]}");
    }
}

Answer 1

OP询问如何在php中执行此操作.这是在php中如何做到这一点:

function sqlPassword($input) {
    $pass = strtoupper(
            sha1(
                    sha1($input, true)
            )
    );
    $pass = '*' . $pass;
    return $pass;
}

为后代添加(没有理由你会使用它,如果mysql决定弃用PASSWORD函数？使用它,仅用于提供信息)mysql相当于php等价物

SELECT 
  UPPER(
    CONCAT('*', SHA1(UNHEX(SHA1('password'))))
  )

另请参阅MySQL Hashing函数实现

Answer 2

如果我理解正确，则无需PASSWORD()在 php 中重现，在 mysql 端一次性执行所有验证，PASSWORD()在您的选择中使用，如下所示

SELECT `username`,`password`,`id`,`disable_until`,`active` 
  FROM `[x]users`
 WHERE `username` = 'user1' 
   AND `password` = PASSWORD('password')

这是SQLFiddle演示

除非您使用区分大小写的排序规则，否则不要LCASE()username在语句中使用on列。如果该列上定义了任何索引，它会阻止 MySql 使用索引并导致对表进行全面扫描。

附带说明：您的代码容易受到 sql 注入的攻击。考虑使用准备好的语句。