Dav*_*idJ 19 graph neo4j cypher
我知道可以使用通配符(*)符号返回Cypher查询中的所有引用,例如:
MATCH p:Product WHERE p.price='1950' RETURN *;
==> +----------------------------------------------------------------+
==> | p |
==> +----------------------------------------------------------------+
==> | Node[686]{title:"Giorgio Armani Briefcase",price:"1950",... |
==> +----------------------------------------------------------------+
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但是,结果是一行具有名为"p"的单个节点"列",可以从中访问属性.但是,我希望结果集"行"将属性名称设置为"列".就像是:
MATCH p:Product WHERE p.price='1950' RETURN p.*;
==> +-------------------------------------------+
==> | title | price | ... |
==> +-------------------------------------------+
==> | "Giorgio Armani Briefcase" | "1950" | ... |
==> +-------------------------------------------+
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该特定查询无效,但有没有办法实现相同的结果(没有明确列出所有属性,如p.title,p.price,p ...)?
Eve*_*man 25
你还不能在Cypher中做到这一点.如果您想要它,我认为这将是一个很好的功能.
编辑(感谢评论指出):您现在可以从2.2开始执行此操作:
MATCH (p:Product) WHERE p.price='1950' RETURN keys(p);
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小智 8
只是为了扩大获取密钥:
MATCH (p:product) WITH DISTINCT keys(p) AS keys
UNWIND keys AS keyslisting WITH DISTINCT keyslisting AS allfields
RETURN allfields;
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这篇博文很好地展示了在 Neo4J 中操作结果
如果您只想获取密钥,上面的回复很好。
如果只想获取属性对象,而不获取
"identity": 16,
"labels": ["Post"],
"properties": { ... }
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你可以做:
MATCH p:Product WHERE p.price='1950' RETURN p{.*};
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这是一个涉及列表的高级示例:
MATCH (post:Post)-[:HAS_JOB]-(job)
OPTIONAL MATCH(post)-[:HAS_LIKE]-(like)
OPTIONAL MATCH (post)-[:HAS_USER]-(user)
WITH post, job, user, collect(like{.*}) as likes
RETURN post{
.*,
likes: likes,
job: job{.*},
user: user{.*}
};
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结果示例:
{
"id": "ec704f3b-ce10-4f23-bd06-6d668b7db488",
"title": "Science Summer"
"job": {
"id": "81ae08e4-57d6-4997-9cb8-407e13bc30c6",
...
},
"user": null,
"likes": [
{
"id": "2209e3a9-701d-4842-9d6b-d4dc8428bac6",
"name": "alex",
...
}
],
}
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这与JavaScript 扩展运算符非常相似。