如何在UIWebView中显示身份验证质询？

Question

我试图通过UIWebView访问一个安全的网站.当我通过safari访问它时,我得到了一个身份验证挑战,但同样的情况并没有出现在应用程序的UIWebView中.我该如何让它出现？

任何指针,示例代码或链接都将非常有用.非常感谢.

Answer 1

这实际上非常简单......我确信你可以在显示auth挑战委托时显示UIAlertView(或者在加载URL之前,如果你确定你正在点击的URL会提示输入身份验证登录信息).无论如何,诀窍是创建自己的NSURLConnection,我做一些逻辑来保存是否已使用auth委托.

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType;
{
    NSLog(@"Did start loading: %@ auth:%d", [[request URL] absoluteString], _authed);

    if (!_authed) {
        _authed = NO;
        /* pretty sure i'm leaking here, leave me alone... i just happen to leak sometimes */
        [[NSURLConnection alloc] initWithRequest:request delegate:self];
        return NO;
    }

    return YES;
}

- (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge;
{
    NSLog(@"got auth challange");

    if ([challenge previousFailureCount] == 0) {
        _authed = YES;
        /* SET YOUR credentials, i'm just hard coding them in, tweak as necessary */
        [[challenge sender] useCredential:[NSURLCredential credentialWithUser:@"username" password:@"password" persistence:NSURLCredentialPersistencePermanent] forAuthenticationChallenge:challenge];
    } else {
        [[challenge sender] cancelAuthenticationChallenge:challenge];
    }
}

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response;
{
    NSLog(@"received response via nsurlconnection");

    /** THIS IS WHERE YOU SET MAKE THE NEW REQUEST TO UIWebView, which will use the new saved auth info **/

    NSURLRequest *urlRequest = [NSURLRequest requestWithURL:[NSURL URLWithString:]];

    [_webView loadRequest:urlRequest];
}

- (BOOL)connectionShouldUseCredentialStorage:(NSURLConnection *)connection;
{
    return NO;
}

Answer 2

您还可以在网址中提供您的凭据.只需在"http://"和"page url"之间添加用户名和密码即可.

NSString *urlString = @"http://username:password@domain.com/home";
[webview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlString]]];