如何编写SQL以获取累积值和每行总计？

Question

说,我有以下数据:

  select 1 id, date '2007-01-16' date_created, 5 sales, 'Bob' name from dual union all
  select 2 id, date '2007-04-16' date_created, 2 sales, 'Bob' name from dual union all
  select 3 id, date '2007-05-16' date_created, 6 sales, 'Bob' name from dual union all
  select 4 id, date '2007-05-21' date_created, 4 sales, 'Bob' name from dual union all
  select 5 id, date '2013-07-16' date_created, 24 sales, 'Bob' name from dual union all
  select 6 id, date '2007-01-17' date_created, 15 sales, 'Ann' name from dual union all
  select 7 id, date '2007-04-17' date_created, 12 sales, 'Ann' name from dual union all
  select 8 id, date '2007-05-17' date_created, 16 sales, 'Ann' name from dual union all
  select 9 id, date '2007-05-22' date_created, 14 sales, 'Ann' name from dual union all
  select 10 id, date '2013-07-17' date_created, 34 sales, 'Ann' name from dual

我想获得如下结果:

Name        Total_cumulative_sales      Total_sales_current_month
Bob         41                          24
Ann         91                          34

在这张表中,对于Bob来说,他的总销售额从一开始就是41.而在本月即7月份,他整个月的销售额为24%.

如何编写SQL来获得此结果？

Answer 1

试试这种方式:

select name, sum(sales) as Total_cumulative_sales ,
       sum( 
            case trunc(to_date(date_created), 'MM')
              when  trunc(sysdate, 'MM') then sales
              else 0
            end
        ) as  Total_sales_current_month

from tab
group by name

SQL小提琴 演示

更多信息

• TRUNC
• 案例陈述