如何将回调样本转换为延迟对象？

Question

我有一个接受回调函数的函数,我将数据传回来.这可以转换为延迟对象以便更好地练习吗？

这是我得到的:

    var chapters;
    var getChapters = function (fnLoad) {
        //CACHE DATA IF APPLICABLE
        if (!chapters) {
            //CALL JSON DATA VIA AJAX
            $.getJSON('/chapters.txt')
                .done(function (json) {
                    //STORE DATA IN LOCAL STORAGE
                    chapters = Lawnchair(function () {
                        this.save(json, function (data) {
                            //CALL CALLBACK ON DATA
                            fnLoad(data);
                        });
                    });
                });
        } else {
            //RETURN ALREADY CREATED LOCAL STORAGE
            chapters.all(function (data) {
                //CALL CALLBACK ON DATA
                fnLoad(data);
            });
        }
    };

然后我就这样使用它:

this.getChapters(function (data) {
    console.log(data);
});

虽然在维护缓存方法的同时如何使用它像一个承诺？

this.getChapters().done(function (data) {
    console.log(data);
});

Answer 1

var chapters;
var getChapters = function (fnLoad) {
    var d = new $.Deferred();
    //CACHE DATA IF APPLICABLE
    if (!chapters) {
        //CALL JSON DATA VIA AJAX
        $.getJSON('/chapters.txt')
            .done(function (json) {
                //STORE DATA IN LOCAL STORAGE
                chapters = Lawnchair(function () {
                    this.save(json, function (data) {
                        //CALL CALLBACK ON DATA
                        d.resolve(data);
                    });
                });
            })
            .fail(function() { d.reject(); });
    } else {
        //RETURN ALREADY CREATED LOCAL STORAGE
        chapters.all(function (data) {
            //CALL CALLBACK ON DATA
            d.resolve(data);
        });
    }
    return d.promise();
};

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