计算每件订单价值超过100美元的商品

Question

我正在努力寻找总价至少250美元的客户订单.然后我需要比较他们每个订单购买的实际商品,看看有多少价值低于或低于100美元.

所以说他们共购买了5件商品.两个价值至少100美元.三个少了.结果将是:

OrderID  LargeItems  SmallItems  Total
1112     2           3           5

这就是我所追求的一个粗略的例子.

现在我有:

--Total Items purchased in orders worth $250 or more
SELECT O.OrderID,COUNT(OP.Price) as 'Total'
FROM dbo.tblOrder O WITH (NOLOCK)
    INNER JOIN dbo.tblOrderProduct OP WITH (NOLOCK)
        ON O.OrderID=OP.OrderID
WHERE O.OrderDate BETWEEN '2011-01-01' AND '2013-01-01'
    and O.Total >= 250
group by O.OrderID
order by O.OrderID

如果你不能轻易说出:

• OP.Pprice是订单中单个商品的价格
• O.Total是订单总额

我错过了大项目和小项目列.我怎样才能将这些单独的计数放入？

谢谢!请询问您是否需要任何额外信息.

Answer 1

您可以使用CASE语句来执行此操作:

SELECT O.OrderID
       ,SUM(CASE WHEN OP.Price >= 100 THEN 1 ELSE 0 END)'LargeItems'
       ,SUM(CASE WHEN OP.Price < 100 THEN 1 ELSE 0 END)'SmallItems'
       ,COUNT(OP.Price) as 'Total'
FROM dbo.tblOrder O WITH (NOLOCK)
    INNER JOIN dbo.tblOrderProduct OP WITH (NOLOCK)
        ON O.OrderID=OP.OrderID
WHERE O.OrderDate BETWEEN '2011-01-01' AND '2013-01-01'
    and O.Total >= 250
group by O.OrderID
order by O.OrderID