在C#中创建类复数

Hei*_*del 2 c#

我尝试用两个不同的构造函数在C#中创建类复数,第一个构造函数采用实部和虚部,第二个构造函数采用模块和参数.

public class Complex
{
    public Complex() { }

    private Complex(double _re, double _im)
    {
        re = _re;
        im = _im;
    }

    public static double Complex_FromCartesian(double _re, double _im)
    {
        return new Complex(_re, _im);
    }

    public static double Complex_FromPolar(double _mod, double _arg)
    {
        var _re = _mod * Math.Cos(_arg);
        var _im = _mod * Math.Sin(_arg);
        return new Complex(_re, _im);
    }

    public static Complex operator +(Complex num1, Complex num2)
    {
        return new Complex(num1.re + num2.re, num2.im + num2.im);
    }

    public static Complex operator -(Complex num1, Complex num2)
    {
        return new Complex(num1.re - num2.re, num2.im - num2.im);
    }

    public double Re { get; set; }
    public double Im { get; set; }

    private double re, im;
}
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}

但是我在两个构造函数中都遇到了同样的错误
在此输入图像描述
如何解决?

DGi*_*bbs 9

您的方法返回一个,double但您正在尝试返回一个Complex类型

更改:

public static double Complex_FromCartesian(double _re, double _im)
{
    return new Complex(_re, _im);
}
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至:

public static Complex Complex_FromCartesian(double _re, double _im)
{
    return new Complex(_re, _im);
}
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  • 它不是构造函数.这是一种静态方法,可以实现您的类类型.调用就像`Complex c = Complex.Complex_FromCartiesian(x,y);`... (3认同)

Moo*_*ght 6

将该方法的返回类型更改为Complex.


gza*_*axx 5

Complex当双倍预期时你不能回来.

public static Complex Complex_FromCartesian(double _re, double _im)
{
   return new Complex(_re, _im);
}
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