Mik*_*Dub 9 wpf datatrigger mvvm
我正在尝试创建一个简单的样式数据触发器,从viewmodel属性中提取它的绑定值,如下所示:
<StackPanel Name="stackTextPanel" Orientation="Horizontal" Margin="0,8,0,0">
<StackPanel.Style>
<Style TargetType="{x:Type StackPanel}">
<Style.Triggers>
<DataTrigger Binding="{Binding QuickDrawBarPinned}" Value="False">
<Setter Property="Margin" Value="0,8,0,0" />
</DataTrigger>
<DataTrigger Binding="{Binding QuickDrawBarPinned}" Value="True">
<Setter Property="Margin" Value="0,48,0,0" />
</DataTrigger>
</Style.Triggers>
</Style>
</StackPanel.Style>
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我也试过这个变种
Binding="{Binding Path=QuickDrawBarPinned}"
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但是当我按下更改QuickDrawBarPinned属性的按钮时,我仍然无法正常工作我做错了什么?
我已经实现了这个属性:
private bool _quickDrawBarPinned = false;
/// <summary>
/// Indicates if the Quick Draw Bar is pinned (stuck) or unpinned (retractable)
/// </summary>
public bool QuickDrawBarPinned
{
get { return _quickDrawBarPinned; }
set
{
_quickDrawBarPinned = value;
OnPropertyChanged("QuickDrawBarPinned");
}
}
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这是实现更改控制的方法
public virtual void OnPropertyChanged(string propertyInfo)
{
App.Current.Dispatcher.BeginInvoke((Action)(() =>
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(propertyInfo));
}
}
));
}
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bli*_*eis 16
我认为你必须删除本地风格的保证金
<StackPanel Name="stackTextPanel" Orientation="Horizontal">
<StackPanel.Style>
<Style TargetType="{x:Type StackPanel}">
<Setter Property="Margin" Value="0,8,0,0" />
<Style.Triggers>
<DataTrigger Binding="{Binding QuickDrawBarPinned}" Value="False">
<Setter Property="Margin" Value="0,8,0,0" />
</DataTrigger>
<DataTrigger Binding="{Binding QuickDrawBarPinned}" Value="True">
<Setter Property="Margin" Value="0,48,0,0" />
</DataTrigger>
</Style.Triggers>
</Style>
</StackPanel.Style>
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