fed*_*qui 10 python multithreading sqlalchemy celery
我有一个连接到MySQL数据库的芹菜项目.其中一个表定义如下:
class MyQueues(Base):
__tablename__ = 'accepted_queues'
id = sa.Column(sa.Integer, primary_key=True)
customer = sa.Column(sa.String(length=50), nullable=False)
accepted = sa.Column(sa.Boolean, default=True, nullable=False)
denied = sa.Column(sa.Boolean, default=True, nullable=False)
Run Code Online (Sandbox Code Playgroud)
此外,在我有的设置
THREADS = 4
Run Code Online (Sandbox Code Playgroud)
我被困在一个函数中code.py:
def load_accepted_queues(session, mode=None):
#make query
pool = session.query(MyQueues.customer, MyQueues.accepted, MyQueues.denied)
#filter conditions
if (mode == 'XXX'):
pool = pool.filter_by(accepted=1)
elif (mode == 'YYY'):
pool = pool.filter_by(denied=1)
elif (mode is None):
pool = pool.filter(\
sa.or_(MyQueues.accepted == 1, MyQueues.denied == 1)
)
#generate a dictionary with data
for i in pool: #<---------- line 90 in the error
l.update({i.customer: {'customer': i.customer, 'accepted': i.accepted, 'denied': i.denied}})
Run Code Online (Sandbox Code Playgroud)
运行时我收到一个错误:
[20130626 115343] Traceback (most recent call last):
File "/home/me/code/processing/helpers.py", line 129, in wrapper
ret_value = func(session, *args, **kwargs)
File "/home/me/code/processing/test.py", line 90, in load_accepted_queues
for i in pool: #generate a dictionary with data
File "/home/me/envs/me/local/lib/python2.7/site-packages/sqlalchemy/orm/query.py", line 2341, in instances
fetch = cursor.fetchall()
File "/home/me/envs/me/local/lib/python2.7/site-packages/sqlalchemy/engine/base.py", line 3205, in fetchall
l = self.process_rows(self._fetchall_impl())
File "/home/me/envs/me/local/lib/python2.7/site-packages/sqlalchemy/engine/base.py", line 3174, in _fetchall_impl
self._non_result()
File "/home/me/envs/me/local/lib/python2.7/site-packages/sqlalchemy/engine/base.py", line 3179, in _non_result
"This result object does not return rows. "
ResourceClosedError: This result object does not return rows. It has been closed automatically
Run Code Online (Sandbox Code Playgroud)
所以主要是它的一部分
ResourceClosedError: This result object does not return rows. It has been closed automatically
Run Code Online (Sandbox Code Playgroud)
有时也会出现这个错误:
DBAPIError :(错误)(,AssertionError('结果长度未请求长度:\n预期= 1.实际= 0.位置:21.数据长度:21',))'SELECT accepted_queues.customer AS accepted_queues_customer,accepted_queues.accepted AS accepted_queues_accepted ,accepted_queues.denied AS accepted_queues_denied \nFROM accepted_queues \nWHERE accepted_queues.accepted =%s OR accepted_queues.denied =%s'(1,1)
我无法正确地重现错误,因为它在处理大量数据时通常会发生.我试图改变THREADS = 4到1和错误消失了.无论如何,它不是一个解决方案,因为我需要保持线程的数量4.
另外,我对使用的必要性感到困惑
for i in pool: #<---------- line 90 in the error
Run Code Online (Sandbox Code Playgroud)
要么
for i in pool.all(): #<---------- line 90 in the error
Run Code Online (Sandbox Code Playgroud)
并且找不到合适的解释.
总之:任何建议跳过这些困难?
zzz*_*eek 12
总之:任何建议跳过这些困难?
是.你绝对不能同时在多个线程中使用Session(或与该Session相关的任何对象)或Connection,特别是对于DBAPI连接非常不安全的MySQL-Python*.您必须组织您的应用程序,以便每个线程处理它自己的专用MySQL-Python连接(以及因此与该Session相关联的SQLAlchemy Connection/Session /对象),而不会泄漏到任何其他线程.
| 归档时间: |
|
| 查看次数: |
11600 次 |
| 最近记录: |