JQuery函数中的错误是什么

Question

我想通过雅虎的API获取天气.功能直到html.我alert在功能之前放了html.什么时候它html显示警报给我.但是当它html不起作用之后.它显示html有错误.问题是什么？

<script type="text/javascript">
    $(document).ready(function () {
        $.simpleWeather({
            zipcode: '',
            woeid: '@Html.DisplayFor(modelItem => item.zipcode)',
            location: '',
            unit: 'c',
            success: function (weather) {
                //html = '<h2>' + weather.city + ', ' + weather.region + '</h2>';
                //html += '<img style="float:left;" width="125px" src="' + weather.image + '">';
                alert("hi");
                html += '<p>' + weather.temp + '&deg; ' + weather.units.temp + '<br /><span>' + weather.currently + '</span></p>';
                html += '<a href="' + weather.link + '">View Forecast &raquo;</a>';

                $("#weather").html(html);
            },
            error: function (error) {
                $("#weather").html('<p>' + error + '</p>');
            }
        });
    });
</script>

现在警报工作

但在此警报不起作用:

<script type="text/javascript">
    $(document).ready(function () {
        $.simpleWeather({
            zipcode: '',
            woeid: '@Html.DisplayFor(modelItem => item.zipcode)',
            location: '',
            unit: 'c',
            success: function (weather) {
                html = '<h2>' + weather.city + ', ' + weather.region + '</h2>';
                html += '<img style="float:left;" width="125px" src="' + weather.image + '">';
                alert("hi");
                html += '<p>' + weather.temp + '&deg; ' + weather.units.temp + '<br /><span>' + weather.currently + '</span></p>';
                html += '<a href="' + weather.link + '">View Forecast &raquo;</a>';

                $("#weather").html(html);
            },
            error: function (error) {
                $("#weather").html('<p>' + error + '</p>');
            }
        });
    });
</script>

这是我的HTML代码:

<div id="weather"></div>

html有错误.请帮帮我 .

Answer 1

您没有初始化也没有声明,html因此该行无法附加到它:

   html += '<p>' + weather.temp + '&deg; ' + ...

你可以html +=改为var html =.

请注意,第二个代码,即使它"有效",仍然没有明确声明html变量(var关键字缺失),这使得它变得全局.