int N = 2345;
var digitArray = N.ToString().ToCharArray();
int multiplicationSum = 1;
foreach (char digit in digitArray)
{
multiplicationSum = int.Parse(digit.ToString()) * multiplicationSum;
}
var sum = 0;
var sumArray = multiplicationSum.ToString().ToCharArray();
foreach (char digit in sumArray)
{
sum = int.Parse(digit.ToString()) + sum;
}
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谢谢
假设你不需要处理负数,那么在数学上做这样做会更有意义
int N = 2345;
int multiplicationSum = 1;
while(N!=0)
{
multiplicationSum = multiplicationSum * (N%10);
N = N/10;
}
var sum = 0;
while(multiplicationSum!=0)
{
sum = sum + (multiplicationSum%10);
multiplicationSum = multiplicationSum/10;
}
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参考文献:
%运算符在将第一个操作数除以第二个操作数后计算余数
/运营商:
除以两个整数后,结果始终为整数.例如,7/3的结果是2