使用Python广播和接收数据

Question

我正在尝试播放一些数据并使用python接收它.这是我提出的代码.

from socket import *
import threading

class PingerThread (threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)

    def run (self):
        print 'start thread'
        cs = socket(AF_INET, SOCK_DGRAM)
        cs.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
        cs.setsockopt(SOL_SOCKET, SO_BROADCAST, 1)
        cs.sendto('This is a test', ('192.168.65.255', 4499))

a = PingerThread() 
a.start()

cs = socket(AF_INET, SOCK_DGRAM)
data = cs.recvfrom(1024) # <-- waiting forever

但是,代码似乎永远等待着cs.recvfrom(1024).可能有什么问题？

Answer 1

代码中有三个问题.

1. 监听器不绑定任何东西.
2. 打开的插座未关闭.
3. 有时,线程生成得如此之快,以至于侦听器只是错过了广播数据.

这是修改后的工作代码.

from socket import *
import time
import threading

port = 4490
class PingerThread (threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)

    def run (self):
        print 'start thread'
        cs = socket(AF_INET, SOCK_DGRAM)
        cs.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
        cs.setsockopt(SOL_SOCKET, SO_BROADCAST, 1)

        time.sleep(0.1) # issue 3 solved
        cs.sendto('This is a test', ('192.168.65.255', port))

a = PingerThread()
a.start()

cs = socket(AF_INET, SOCK_DGRAM)
try:
    cs.bind(('192.168.65.255', port)) # issue 1 solved
except:
    print 'failed to bind'
    cs.close()
    raise
    cs.blocking(0)

data = cs.recvfrom(20)  
print data
cs.close() # issue 2 solved