Dav*_*ave 1 spring hibernate jpa orphaned-objects
我正在使用JPA 2.0,Hibernate 4.1.0.Final,Spring 3.1.1.RELEASE和Java 1.6.我有这个实体与另一个实体的一对多关系......
import javax.persistence.CascadeType;
...
@Entity
@Table(name = "classroom")
public class Classroom implements Serializable
{
...
@OneToMany(mappedBy = "classroom", cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REMOVE})
private Set<ClassroomUser> roster;
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但是,当我使用一组不同的ClassroomUser对象更新我的实体时
classroom.setRoster(newRoster);
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并保存实体,保留所有以前的ClassroomUser对象.在从数据库中删除所有孤立记录时更新我的实体的正确/最短方法是什么?
谢谢, - 戴夫
用途orphanRemoval:
@OneToMany(mappedBy="classroom", cascade={CascadeType.ALL}, orphanRemoval=true)
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每当从持久集中删除条目时,它将被删除.这意味着您需要使用持久集.即你不能更换套装,而应该做:
classroom.getRoster().clear();
classroom.getRoster().addAll(newRoster);
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示例如何将持久集与用户所需的集同步:
/**
* Assemble ClassroomUser relations.
* @param classroom Classroom entity. Must be attached persistent or transient. Never null.
* @param userIds Collection of user identifiers. Can be empty. Never null.
*/
private void assembleClassroomUsers(Classroom classroom, Collection<Integer> userIds) {
// Make sure relation set exists (might be null for transient instance)
if (classroom.getUsers() == null) {
classroom.setUsers(new HashSet<ClassroomUser>());
}
// Create working copy of the collection
Collection<Integer> ids = new HashSet<Integer>(userIds);
// Check existing relations and retain or remove them as required
Iterator<ClassroomUser> it = classroom.getUsers().iterator();
while (it.hasNext()) {
Integer userId = it.next().getUser().getId();
if (!ids.remove(userId)) {
it.remove(); // This will be picked by the deleteOrphans=true
}
}
// Create new relations from the remaining set of identifiers
for (Integer userId : ids) {
ClassroomUser classroomUser = new ClassroomUser();
classroomUser.setClassroom(classroom);
// User must not have ClassroomUser relations initialized, otherwise Hibernate
// will get conflicting instructions what to persist and what to drop => error.
// It might be safer to use dummy transient instance...
User dummyUser = new User();
dummyUser.setId(userId);
classroomUser.setUser(dummyUser);
classroom.getUsers().add(classroomUser);
}
}
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这种方法看起来有点复杂.您可以使用自定义equals/ hashCode和一些Set<E>操作方法(例如来自Guava)创建更简单(但可能不太多)的东西.
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