为什么在有效索引位置删除时,splice方法返回undefined？

Question

为什么splice方法返回undefined并且不删除以下代码中位置4的元素:

var excludedDepartmentsList = [1, 2, 3, 4, 5, 6];
var currentDepartmentId = 5;

var position = $.inArray(currentDepartmentId, excludedDepartmentsList);

if (position > -1) {
    var q = excludedDepartmentsList.splice[position, 1];
    return;
}

我在这里做了一个测试:http://jsfiddle.net/PnVEb/

Answer 1

.splice是一个函数,它应该被调用,excludedDepartmentsList.splice(position, 1)而不是excludedDepartmentsList.splice[position, 1].请注意括号从更改[]为().

使用()如下,它应该返回5

excludedDepartmentsList.splice(position, 1)

固定小提琴: http ://jsfiddle.net/PnVEb/1/