Pey*_*man 12 php android push-notification google-cloud-messaging
我对Google Cloud Messaging有疑问......
我将GCM发送给Google以获取3个注册ID,然后Google回复说已成功发送了2个注册ID而没有注册ID,因为注册ID错误!
但它没有告诉我哪个注册ID尚未发送...
现在我的问题是:如何解析Google GCM响应以获取尚未发送的注册ID?谷歌是否有API或其他东西,以便我可以给它"multicat_id",它告诉我哪个注册ID有问题?
任何帮助都会非常感激,我只是很困惑:)
Era*_*ran 15
它基于订单:
假设你发送这个:
{ "collapse_key": "score_update",
"time_to_live": 108,
"delay_while_idle": true,
"data": {
"score": "4x8",
"time": "15:16.2342"
},
"registration_ids":["4", "8", "15", "16", "23", "42"]
}
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并得到Google的回复:
{ "multicast_id": 216,
"success": 3,
"failure": 3,
"canonical_ids": 1,
"results": [
{ "message_id": "1:0408" },
{ "error": "Unavailable" },
{ "error": "InvalidRegistration" },
{ "message_id": "1:1516" },
{ "message_id": "1:2342", "registration_id": "32" },
{ "error": "NotRegistered"}
]
}
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这意味着您发送的第3个注册ID(15)无效,第6个(42)未注册.两者都应从您的数据库中删除.
小智 9
我是这样做的:
$gcm_result = $gcm->send_notification($registration_ids, $message);
$jsonArray = json_decode($gcm_result);
if(!empty($jsonArray->results)){
$remove_ids = array();
for($i=0; $i<count($jsonArray->results);$i++){
if(isset($jsonArray->results[$i]->error)){
if($jsonArray->results[$i]->error == "NotRegistered"){
$remove_ids[$i] = "'".$registration_ids[$i]."'";
}
}
}
if(!empty($remove_ids)){
$remove_ids_string = implode(', ',$remove_ids);
include_once SCRIPTS.'gcm_server_php/db_functions.php';
$dbf = new DB_Functions();
$res = $dbf->deleteUsers($remove_ids_string);
echo count($remove_ids)." users have unregistered from notifications since the last one was sent out.";
}
}
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