use*_*806 5 haskell generic-programming scrap-your-boilerplate
将转换仅应用于树而不是everywhere使用SYB 的最佳方法是什么?例如,在下面的简化表达式中,有几个实例Var "x",我想只用第一个实例替换Var "y".
data Exp = Var String
| Val Int
| Plus Exp Exp
|...
myExp = Val 5 `Plus` Var "x" `Plus` Val 5 `Plus` Var "x" ...
everywhereVar "x"
这不能用做Var "y"组合子,因为它会尝试改变的所有实例somewhere来everywhere.
编辑(发布后):看起来就像Var "x"我在寻找.
作为一名 SYB 初学者,我的答案更像是一个猜测,但似乎可行。
Neil Brown 推荐的Combinatorsomewhere可能并不能完全满足您的要求。它定义为
-- | Apply a monadic transformation at least somewhere
somewhere :: MonadPlus m => GenericM m -> GenericM m
-- We try "f" in top-down manner, but descent into "x" when we fail
-- at the root of the term. The transformation fails if "f" fails
-- everywhere, say succeeds nowhere.
--
somewhere f x = f x `mplus` gmapMp (somewhere f) x
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在哪里
-- | Transformation of at least one immediate subterm does not fail
gmapMp :: forall m. MonadPlus m => (forall d. Data d => d -> m d) -> a -> m a
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但我们最多需要改造一次。为此,似乎gmapMo会更好:
-- | Transformation of one immediate subterm with success
gmapMo :: forall m. MonadPlus m => (forall d. Data d => d -> m d) -> a -> m a
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所以我制作了自己的组合器:
{-# LANGUAGE DeriveDataTypeable, RankNTypes #-}
import Control.Monad
import Data.Maybe (fromMaybe)
import Data.Data
import Data.Typeable (Typeable)
import Data.Generics.Schemes
import Data.Generics.Aliases
-- | Apply a monadic transformation once.
once :: MonadPlus m => GenericM m -> GenericM m
once f x = f x `mplus` gmapMo (once f) x
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如果替换失败,则返回mzero,否则返回替换后的结果。如果您不关心替换是否失败(没有匹配项),您可以使用类似的东西
once' :: (forall a. Data a => a -> Maybe a) -> (forall a. Data a => a -> a)
once' f x = fromMaybe x (once f x)
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有了这些,我们可以做一些替换:
data Exp = Var String | Val Int | Plus Exp Exp
deriving (Show, Typeable, Data)
myExp = Val 5 `Plus` Var "x" `Plus` Val 5 `Plus` Var "x"
replM :: (MonadPlus m) => Exp -> m Exp
replM (Var "x") = return $ Var "y"
replM t = mzero
main = do
-- `somewhere` doesn't do what we want:
print $ (somewhere (mkMp replM) myExp :: Maybe Exp)
-- returns `Just ..` if the substitution succeeds once,
-- Nothing otherwise.
print $ (once (mkMp replM) myExp :: Maybe Exp)
-- performs the substitution once, if possible.
print $ (once' (mkMp replM) myExp :: Exp)
-- Just for kicks, this returns all possible substitutions
-- where one `Var "x"` is replaced by `Var "y"`.
print $ (once (mkMp replM) myExp :: [Exp])
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