Java - 在将用户输入读入数组时跳过一行(for循环)

JPw*_*ire 6 java java.util.scanner

这是我的代码 - 目的是为x个患者输入一些基本信息(年龄,姓名,性别).

public static void main(String[] args) {

    int numPatients = 2;

    int[] age = new int[numPatients];
    String[] gender = new String[numPatients];
    String[] name = new String[numPatients];
    Scanner in = new Scanner(System.in);

    /*
     * Obtaining patients details: name, gender, age
     * First create a Scanner input variable to read the data
     */
    for (int i = 0; i < numPatients; i++)
    {
    System.out.println("Enter name of patient " + (i+1));
     name[i] =  in.nextLine();

    System.out.println("Enter gender (male/female) of patient " + (i+1));
     gender[i] =  in.nextLine();

    System.out.println("Enter age of patient " + (i+1));
     age[i] =  in.nextInt();
    }
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我遇到的问题是当循环转到第二个变量时,即我无法输入患者姓名的值.它似乎跳过那里的输入并直接进入下一个输入,即性别.

Enter name of patient 1
Mark
Enter gender (male/female) of patient 1
Male
Enter age of patient 1
34
Enter name of patient 2 //Skipped. Could not enter input here
Enter gender (male/female) of patient 2
Jenna
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知道为什么会这样吗?是否更好地使用BufferedReader?

Gre*_*ill 7

如果必须使用Scanner,则始终使用nextLine().问题是nextInt()读取输入的整数部分并在读取Enter键之前停止.然后下一次调用以查看缓冲区中的Enter键和您输入的空名称.nextLine()

所以你可以这样做:

age[i] = Integer.parseInt(in.nextLine());
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并准备好处理用户键入除数字以外的其他内容时发生的异常.