Dav*_*rno 5 javascript arrays sorting
我有一个类似于这个的数组设置:
var ary1 = new Array("d", "a", "b", "c");
var ary2 = new Array("ee", "rr", "yy", "mm");
var mdAry = new Array(ary1, ary2);
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ary1和ary2索引是在宏观方案中相互关联的信息.
d ee
a rr
b yy
c mm
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我可以排序()ary1并得到:
a
b
c
d
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但如果我独立排序ary2,我会得到:
ee
mm
rr
yy
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在列出时可视地打破ary1和ary2连接.我可以检索ary1的排序解决方案并将其应用于ary2吗?我想得到这个:
a rr
b yy
c mm
d ee
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如果没有,可以对mdAry进行排序,以便将mdAry [0]排序解决方案应用于其余的指标吗?
您可以将它们“合并”为具有两个属性的单个对象,按第一个属性排序,然后最后分开(请参阅此处的演示):
function sortBoth(ary1, ary2) {
var merged = [];
for (var i=0; i < ary1.length; i++) merged.push({'ary1': ary1[i], 'ary2': ary2[i]});
merged.sort(function(o1, o2) { return ((o1.ary1 < o2.ary1) ? -1 : ((o1.ary1 == o2.ary1) ? 0 : 1)); });
for (var i=0; i < merged.length; i++) { ary1[i] = merged[i].ary1; ary2[i] = merged[i].ary2; }
}
var ary1 = new Array("d", "a", "b", "c");
var ary2 = new Array("ee", "rr", "mm", "yy");
console.log(ary1);
console.log(ary2);
sortBoth(ary1, ary2);
console.log(ary1);
console.log(ary2);
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输出:
[ "d", "a", "b", "c"]
["ee", "rr", "mm", "yy"]
[ "a", "b", "c", "d"]
["rr", "mm", "yy", "ee"]
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