当我通过<f:subview>标签访问时,为什么找不到<h:panelGroup> id？

Question

 <h:panelGroup id="userPanel"><f:subview rendered="#{searchView.isUser}">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"   >
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton> </f:subview></h:panelGroup>

我收到错误:无法在组件j_idt26的上下文中找到它

Answer 1

因为<f:subview>是NamingContainer.

也可以看看:

• 如何找到ajax update/render组件的客户端ID？找不到带有"bar"引用的表达式"foo"的组件

只是用<h:panelGroup>,

<h:panelGroup id="userPanel">
    <h:panelGroup rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </h:panelGroup>
</h:panelGroup>

或者<ui:fragment>(只有少许开销)

<h:panelGroup id="userPanel">
    <ui:fragment rendered="#{searchView.isUser}">
        <h:commandButton value="test" action="#{searchAction.doFindUsers}">
            <f:ajax execute="@this" event="action" render="userPanel" />
        </h:commandButton>
    </ui:fragment>
</h:panelGroup>

或者在这个具体的例子中直接在命令按钮上(当然你的情况比这更复杂)

<h:panelGroup id="userPanel">
    <h:commandButton value="test" action="#{searchAction.doFindUsers}"  rendered="#{searchView.isUser}">
        <f:ajax execute="@this" event="action" render="userPanel" />
    </h:commandButton>
</h:panelGroup>

也可以看看:

• 替代ui:JSF中的片段
• 非JSF组件的条件呈现(普通的HTML和模板文本)