变量的平均值由两个因素决定

Ben*_*Ben 11 r tapply

我有以下数据:

a <- c(1,1,1,1,2,2,2,2)
b <- c(2,4,6,8,2,3,4,1)
c <- factor(c("A","B","A","B","A","B","A","B"))
df <- data.frame(
    sp=a,
    length=b,
    method=c)
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我可以使用以下方法通过方法计算每个物种的样本数量:

n <- with(df,tapply(sp,method,function(x) count(x)))
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我如何通过每个物种的方法获得平均长度?

use*_*1_G 13

我个人会用aggregate:

aggregate(length ~ sp, data = df, FUN= "mean" )
# by species only
#     sp length
#1  1    5.0
#2  2    2.5

aggregate(length ~ sp + method, data = df, FUN= "mean" )
    # by species and method
#  sp method length
#1  1      A      4
#2  2      A      3
#3  1      B      6
#4  2      B      2
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为了你可能想要的一切:

aggregate(length ~ method, data = df, function(x) c(m = mean(x), counts = length(x)) )

# counts and mean for each method
#  method length.m length.counts
#1      A      3.5           4.0
#2      B      4.0           4.0
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Adr*_*ian 5

图书馆plyr对这样的东西很有帮助

library(plyr)
new.df <- ddply(df, c("method", "sp"), summarise,
                mean.length=mean(length),
                max.length=max(length),
                n.obs=length(length))
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给你

> new.df
  method sp mean.length max.length n.obs
1      A  1           4          6     2
2      A  2           3          4     2
3      B  1           6          8     2
4      B  2           2          3     2
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有关更多示例,请访问http://www.inside-r.org/packages/cran/plyr/docs/ddply.